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Vedmedyk [2.9K]
3 years ago
14

Which of these physical concepts is most important in civil engineering?

Engineering
1 answer:
mezya [45]3 years ago
3 0

Answer:

Option A (energy transformations) is the correct solution.

Explanation:

  • Energy has become a local matter that has been primarily described as the commitment to deal as well as to generate heat. There are several other power sources, which can either be transferred or transformed to several other renewable technologies.  
  • This same fundamental law defined that the energy required including its universe has been corrected and therefore that energy is being generated as well as severely damaged but should only be moved from one location to the next.

Those certain possibilities are not connected to the circumstance in question. And therefore this answer seems to be the correct one.

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The cross-section of a rough, rectangular, concrete() channel measures . The channel slope is 0.02ft/ft. Using the Darcy-Weisbac
bazaltina [42]

Answer:

The following are the answer to this question:

Explanation:

In point a, Calculating the are of flow:

\bold{Area =B \times D_f}

         =6\times 5\\\\=30 \ ft^2

In point b, Calculating the wetter perimeter.

\bold{P_w =B+2\times D_f}

      = 6 +2\times (5)\\\\= 6 +10 \\\\=16 \ ft

In point c, Calculating the hydraulic radius:

\bold{R=\frac{A}{P_w}}

   =\frac{30}{16}\\\\= 1.875 \ ft

In point d, Calculating the value of Reynolds's number.

\bold{Re =\frac{4VR}{v}}

     =\frac{4V \times 1.875}{1 \times 10^{-5} \frac{ft^2}{s}}\\\\

     =750,000 V

Calculating the velocity:

V= \sqrt{\frac{8gRS}{f}}

   = \sqrt{\frac{8\times 32.2 \times 1.875 \times 0.02}{f}}\\\\=\frac{3.108}{\sqrt{f}}\\\\

\sqrt{f}=\frac{3.108}{V}\\\\

calculating the Cole-brook-White value:

\frac{1}{\sqrt{f}}= -2 \log (\frac{K}{12 R} +\frac{2.51}{R_e \sqrt{f}})\\\\ \frac{1}{\frac{3.108}{V}}= -2 \log (\frac{2 \times 10^{-2}}{12 \times 1.875} +\frac{2.51}{750,000V\sqrt{f}})\\

\frac{V}{3.108} =-2\log(8.88 \times 10^{-5} + \frac{3.346 \times 10^{-6}}{750,000(3.108)})

After calculating the value of V it will give:

V= 25.18 \ \frac{ft}{s^2}\\

In point a, Calculating the value of Froude:

F= \frac{V}{\sqrt{gD}}

= \frac{V}{\sqrt{g\frac{A}{\text{Width flow}}}}\\

= \frac{25.18}{\sqrt{32.2\frac{30}{6}}}\\\\= \frac{25.18}{\sqrt{32.2 \times 5}}\\\\= \frac{25.18}{\sqrt{161}}\\\\=  \frac{25.18}{12.68}\\\\= 1.98

The flow is supercritical because the amount of Froude is greater than 1.  

Calculating the channel flow rate.

Q= AV

   =30x 25.18\\\\= 755.4 \ \frac{ft^3}{s}\\

4 0
3 years ago
The primary of an ideal transformer has 400 turns and its secondary has 200 turns. Neglecting electrical losses, if the power in
Vanyuwa [196]

Answer:

A.C. Voltage (transformers only work with A.C.) from input (primary) to output (secondary) is purely a function of the turns ratio.

Explanation:

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2 years ago
A motor vehicle has a mass of 1200kg and the road wheels have a radius of 360mm. The engine rotating parts have a moment of iner
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Answer:

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Explanation:

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3 years ago
TWO SENTENCES!!! What is something that you have used today that was designed by an engineer? What parts were designed by an eng
svetlana [45]
Cars, houses, Devices. :)
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3 years ago
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What is the purpose of the graphic language?
solmaris [256]

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enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

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3 years ago
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