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Mariulka [41]
3 years ago
7

A circuit has a resistance of 2.5 Ω and is powered by a 12.0 V battery.

Physics
1 answer:
Marizza181 [45]3 years ago
5 0

Just apply Ohm's Law:


I=V/R=12/2.5=4.8A

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What force must the worker exert to get the box moving & what force must the worker exert to accelerate the box at 0.1 meter
photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

F - F_k = m*a

here

F_k = kinetic friction = 220 N

m = mass = 500 kg

a = acceleration = 0.1 m/s^2

now we will have

F - 220 = 500* 0.1

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3 0
3 years ago
Metal sphere A has a charge of -2 units and an identical sphere B has a charge of -4 units. If the spheres are brought into cont
shusha [124]

Answer:

 q1 = q₂=  -3

therefore each sphere has the same charge of -3 untis

Explanation:

The metallic spheres have mobile charge, so when the two spheres come into contact the total charge

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it is distributed in between the two spheres evenly since the charges of the same sign repel each other.

When the spheres separate each one has

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5 0
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Give two examples of human activity that affect the earth systems
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The net torque exerted by the children on the branch of the tree is 1382 N-m.

The torque exert by the kids is calculated as

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Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.

7 0
4 years ago
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stepan [7]

To solve this problem we will apply the concepts of Pythagoras to find the net path. An easy way is to graph the path to trace the path, which resembles that of a right triangle. The information provided is equivalent to that of the two short sides of the triangle, so we will find the longest side by the Pythagorean theorem. In this way,

OC = \sqrt{2^2+2.4^2}

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6 0
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