A 0.80-kg soccer ball experinces an impulse of 25 N x s . Determine the momentum change of the soccer ball.
2 answers:
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(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.
Thus, there is no acceleration, when velocity is constant.
(b) Average acceleration,
Here, v is final velocity and u is the initial velocity and is the time interval.
As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore
Thus, the average acceleration of the car is in the direction to the left.
Answer:
a) 9.46M m/s^2
b) 48.83m
c) 68.22m/s
Explanation:
The centripetal force must be equal to the horizontal component (x component) of the gravitational force over the plum bob. Thus, we have
( 1 )
where M is the mass of the car, v its speed, r the radius of the curvature and g the gravity constant.
a) By replacing we obtain:
( 2 )
where it is only necessary to put the mass of the car M in (2).
b) By canceling M in (2) and taking apart r we get:
c) If the angle is 7° the speed is given by:
hope this helps!!
The momentum of each cart is given by:
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)
2)
3)
4)
Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)
2)
3)
4)
Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>