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vladimir2022 [97]
2 years ago
9

Which element has two valence electrons?

Chemistry
2 answers:
Colt1911 [192]2 years ago
6 0

Answer:

It is A) Calcium

Explanation:

Calcium has an electronic configuration of 2,8,8,2

Alenkinab [10]2 years ago
5 0

Answer: The answer is A! hope this helps :)

Explanation: Calcium has 2 valence electron.

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HELP!!!!!
faltersainse [42]

Answer:

5.17.

Explanation:

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

[OH⁻] = 1.5  x 10⁻⁹ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5  x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(6.66 × 10⁻⁶ M) = 5.17. </em>

5 0
3 years ago
Read 2 more answers
What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?
Roman55 [17]
Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 =  58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm
5 0
3 years ago
Which lists the structures, in correct order, through which light passes when it enters the eye?
Mashutka [201]

Answer:

cornea, pupil, lens, vitreous humor

8 0
3 years ago
A. 1720 kJ<br> B. 125.6 kJ<br> C. 3440 kJ<br> D. 4730 kJ
Feliz [49]

Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

Latent heat of vaporization = 1720 Kj/Kg

Energy required to vaporize 2kg gold = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  1720 Kj/Kg

Q = 3440Kj

7 0
3 years ago
What is the standard heat of reaction for the following reaction?
8090 [49]

Answer:

The correct answer to the question is

The standard heat of reaction for the reaction is

a. 216.8 kJ released per mole

Explanation:

The heat of reaction is given by [Heat of formation of products] - [Heat of formation of reactants]

In the question we have, heat of formation of the products Zn+2 (aq) = -152.4 kJ/mole and the heat of formation of the reactants = 64.4 kJ/mole

Therefore, the heat of formation of the reaction = (-152-64.4) kJ/mole or

-216.8 kJ/mole released

5 0
3 years ago
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