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Bogdan [553]
3 years ago
15

No interior de um calorímetro de capacidade térmica 6 cal/°C encontram-se 85 g de um líquido a 18°C. Um bloco de cobre de massa

120 g e calor específico 0,094 cal/g°C, aquecido a 100°C, é colocado dentro do calorímetro. O equilíbrio térmico se estabelece a 42°C. Determine o calor específico do líquido.

Physics
2 answers:
MrRissso [65]3 years ago
4 0

Answer:

Heat Exchange

Explanation:

<em>Within a 6 cal / ° C thermal capacity calorimeter is 85 g of a liquid at 18 ° C. A block of copper of mass 120 g and specific heat 0.094 cal / g ° C, heated to 100 ° C, is placed within the calorimeter. The thermal equilibrium is established at 42 ° C. Determine the specific heat of the liquid.</em>

I will add the answer as an image, as the system encounters Bug and warns that there are external links in the response.

Lyrx [107]3 years ago
3 0

a fórmula do calor sensível é Q = m.c.ΔT


m = massa

c = calor específico do corpo

ΔT = variação de temperatura (Tf - Ti)


quando ocorre o equilíbrio térmico, a soma dos calores trocados entre os corpos é 0:

QA + QB + QC = 0

sabendo que a capacidade térmica é o produto m.c e substituindo os demais valores fornecidos no enunciado:


QA = calor sensível do calorímetro = (6 cal/°C).(42-18)

QB = calor sensível do líquido =  (85g).c.(42-18)

QC = calor sensível do bloco =  (120g).(0,094 cal/g°C).(42-100)


substituindo na expressão para calcular c, o calor específico do líquido :


(6 cal/°C).(42°C-18°C) +  (85g).c.(42°C-18°C) + (120g).(0,094 cal/g°C).(42°C-100°C) = 0


144cal + 2040c - 654,2cal = 0


 2040c = 510cal


c = 510cal/2040g.°C


c = 0,25cal/g.°C


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