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Scrat [10]
2 years ago
9

at maximum extension a bungee cord stores 2.0 X 10^6 J of energy. A 10 kg mass extends the bungee cord 1.3m. what is the maximum

extension of the bungee cord.​
Physics
1 answer:
Gnoma [55]2 years ago
4 0

Explanation:

A k E increases While P E Decreases

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The most common type of dam is an impoundment hydroelectric plant, which consists of a dam across a river, and a reservoir (lake
Naya [18.7K]

Answer:

A turbine spins the water to generate electricity.

Explanation:

This is impoundment facility is called a hydro electric power dam, it is basically a big hydropower system which uses the dam to store river water in a reservoir. The water released from the reservoir flows directly through a turbine, the turbine spins it, which afterwards activates a generator to generate electricity.

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3 years ago
What is the speed of a person that walk 400 meters in 1900 seconds
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Answer:

Explanation:

.

6 0
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If a current of one- or two-tenths of an ampere were to flow into one of your hands and out the other, you would probably be ele
musickatia [10]

Fjtffgh

Explanation:d3d

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3 0
3 years ago
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If a certain mass of mercury has a volume of 0.002 m^3 at a temperature of 20°c, what will be the volume at 50°c
V125BC [204]
Change in volume = mass x coefficient of linear expansion x change in temperature
.002 x .0001802 x 30 = .000010812

initial volume + change in volume = Final volume
.002 + .000010812 = .002010812 m cubed
5 0
3 years ago
Read 2 more answers
Physics help, thank you guys so much!
katrin2010 [14]

Answer:

 Δt = 5.85 s

Explanation:

For this exercise let's use Faraday's Law

           emf = -  \frac{d \phi}{dt} -  d fi / dt

           \phi = B. A

           \phi = B A cos θ

The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.

suppose a linear change of the magnetic field

            emf = - A \frac{B_f - B_o}{ \Delta t}

             Dt = - A  \frac{B_f - B_o}{emf}

the final field before a fault is zero

       

let's calculate

            Δt = - 0.046 (0- 1.4) / 0.011

            Δt = 5.85 s

4 0
2 years ago
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