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zlopas [31]
2 years ago
7

*BRAINLIEST BRAINLIEST

Chemistry
1 answer:
Lena [83]2 years ago
8 0

Answer:

THE 3 third one

Explanation:

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PLEASE HELP!!!
Kaylis [27]
I think it comes from Fungi. I'm not 100% sure about that though.
8 0
2 years ago
1.15 g of a metallic element needs 300 cm3 of oxygen for complete reaction, at 298 K and 1 atm
sashaice [31]
1) Calculate the number of moles of O2 (g) in 300 cm^3 of gas at 298 k and 1 atm


Ideal gas equation: pV = nRT => n = pV / RT


R = 0.0821 atm*liter/K*mol

V = 300 cm^3 = 0.300 liter

T = 298 K

p = 1 atm


=> n = 1 atm * 0.300 liter / [ (0.0821 atm*liter /K*mol) * 298K] = 0.01226 mol


2) The reaction of a metal with O2(g) to form an ionic compound (with O2- ions) is of the type


X (+) + O2 (g) ---> X2O          or   


2 X(2+) + O2(g) ----> X2O2 = 2XO     or


4X(3+) + 3O2(g) ---> 2X2O3


 
In the first case, 1 mol of metal react with 1 mol of O2(g); in the second case, 2 moles of metal react with 1 mol of O2(g); in the third, 4 moles of X react with 3 moles of O2(g)



So, lets probe those 3 cases.


3) Case 1: 1 mol of metal X / 1 mol O2(g) = x moles / 0.01226 mol

=> x = 0.01226 moles of metal X


Now you can calculate the atomic mass of the hypotethical metal:

1.15 grams / 0.01226 mol = 93.8 g / mol


That does not correspond to any of the metal with valence 1+


So, now probe the case 2.



4) Case 2:


2moles X metal / 1 mol O2(g) = x / 0.01226 mol


=> x = 2 * 0.01226 = 0.02452 mol


And the atomic mass of the metal is: 1.15 g / 0.02452 mol = 46.9 g/mol


That is similar to the atomic mass of titanium which is 47.9 g / mol and whose valece is 2+.


4) Case 3


4 mol meta X / 3 mol O2 = x / 0.01226 => x = 0.01226 * 4 / 3 = 0.01635 


atomic mass = 1.15 g / 0.01635 mol = 70.33 g/mol


That does not correspond to any metal.


Conclusion: the identity of the metallic element could be titanium.
5 0
3 years ago
Which water cycle processes might be responsible for helping to clean/ filter the water? Explain.
Leya [2.2K]

to be as exact as i can it is all of them they all work together to make water good.


7 0
3 years ago
4) What mass of hydrogen is formed when 2.00g of magnesium<br> Mg + H2SO4–&gt;H2SO4
DochEvi [55]

Answer:

0.16g

Explanation:

Please mark as brainliest

7 0
2 years ago
Read 2 more answers
At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)&lt;---&gt;2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an
SOVA2 [1]

<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

                      Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)

<u>Initial:</u>                                                                  0.902

<u>At eqllm:</u>                            3x                           (0.902-3x)

The expression of K_p for above equation follows:

K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}

We are given:

K_p=19.9

Putting values in above equation, we get:

19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0
3 years ago
Read 2 more answers
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