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zlopas [31]
2 years ago
7

*BRAINLIEST BRAINLIEST

Chemistry
1 answer:
Lena [83]2 years ago
8 0

Answer:

THE 3 third one

Explanation:

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masha68 [24]

Answer:

heat

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climate

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6 0
3 years ago
Read 2 more answers
The fission of an atom that has a larger atomic number can be induced by bombarding the atom with
vova2212 [387]
Hello!

The fission of an atom that has a large atomic number can be induced by bombarding the atom with neutrons.

Nuclear fission occurs when a heavy nucleus divides into two or more lighter nuclei. This reaction is induced by the bombarding of neutrons into the nucleus, making it unstable (like throwing an orange to a perfectly arranged orange pyramid at the supermarket). The unstable nucleus breaks down into lighter elements, releasing more neutrons which contribute to the chain reaction.

Have a nice day!
5 0
3 years ago
Why do you think some of the indicators used in experiment 2 were different than the ones used in experiment 1?
pentagon [3]

During selection of indicator. We choose an indicator which have pH range equivalent to the pH change of reaction to give better result and better observation.

So there are some different indicator are used in table 2 as compared to the table 1. 

- Alizarin and phenolphthalein are basic indicator and their pH range is more than 8 so they are used in table 2

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6 0
3 years ago
How many grams of NaCl are in 0.50 moles of NaCl?
Semmy [17]
Hope this helps! 29.221385
7 0
3 years ago
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
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