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PilotLPTM [1.2K]
3 years ago
5

Object A: has a mass of 2g a volume of .5L

Chemistry
1 answer:
malfutka [58]3 years ago
8 0
An object will be floating in water if the density is lower and will be sink if the density is higher. Water density would be 1000g/liter or 1g/ml. To determine whether the object float or sink you need to calculate both object density.

The density of object A would be: 2g/ 0.5liter= 4g/liter
The density of object B would be: 3g/ 5liter= 0.6g/liter

It is clear that the object is much lighter than water so both objects would float.
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Balance this chemical equation. Choose "blank" for the box if no other coefficient is needed. Writing the symbol implies "1."
DENIUS [597]

Answer: 3NH_4OH+AlCl_3\rightarrow Al(OH)_3+3NH_4Cl

Explanation: A double displacement reaction is one in which exchange of ions take place.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

3NH_4OH+AlCl_3\rightarrow Al(OH)_3+3NH_4Cl

4 0
3 years ago
Why is the energy supplied by the cooker greater than that calculated ?
TEA [102]

Answer:

Explanation:

Q1.

(a) 46 200

accept 46 000

allow 1 mark for correct substitution

ie 0.5 × 4200 × 22 provided no subsequent step

2

(b) Energy is used to heat the kettle.

[3]

Q2.

(a) (approximate same size particles as each other and as liquid and gas) touching

do not accept particles that overlap

regular arrangement (filling the square)

(b) condensing

(c) solid

(d) physical

(e) particles have more kinetic energy

particles move faster

(f) mass of the liquid

specific latent heat of evaporation

(g) 2 × 4 200 × 801

672 000 (J)

an answer of 672 000 (J) scores 2 marks

[11]

Q3.

(a) x-axis labelled and suitable scale

Page 12 of 13

points plotted correctly

allow 5 correctly plotted for 2 marks, 3−4

correctly plotted for 1 mark

allow ± ½ square

2

line of best fit

(b)

allow ecf from line of best fit in part (a)

0.075 (°C/s)

an answer of 0.075 (°C/s) scores 2 marks

(c) Δθ = 11.5 (°C)

a calculation using an incorrect temperature

scores max 3 marks

ΔE = 1.50 × 900 × 11.5

ΔE = 15 525 (J)

ΔE = 15.525 (kJ)

an answer of 15.525 (kJ) or 15.53 (kJ) or 15.5

(kJ) scores 4 marks

an answer of 15 525 (kJ) scores 3 marks

[10]

Q4.

(a) 80 °C

ΔE = 0.5 × 3400 × 80

ΔE = 136 000 (J)

an answer of 136 000 (J) scores 3 marks

(b) energy is dissipated into the surroundings

allow any correct description of wasted energy

(c) put a lid on the pan

allow any sensible practical suggestion

eg add salt to the water

Page 13 of 13

(d) efficiency = 300/500

efficiency = 0.6

an answer of 0.6 or 60% scores 2 marks

allow efficiency = 60%

an answer of 0.6 with a unit scores 1 mark

an answer of 60 without a unit scores 1 mark

7 0
2 years ago
Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density
Anestetic [448]

Answer:

5.96 g/cm^3

Explanation:

Corner atom = 1/8

Atoms in center = 1

Atoms in face of the cube= 1/2  

Molar mass of V = 50.94 g/mol <em>(from period table)</em>

1 mole = 6.02x10^23

<em>In BCC unit cell:</em>

(8 x 1/8)+ 1=2 per 1 unit cell

<em>Mass: </em>2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell

305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)

           = 2.837 x 10^-23 mL

<em>1pm=10^-12m</em>

<em>1cm=10^-2m</em>

<em>1mL=1cm^3</em>

<em></em>

density=mass/volume

density of V = 1.69x10^-22g÷2.837x10^-23mL

                    =5.957g/mL

                    =5.96g/cm^3

5 0
2 years ago
Can anyone answer this ASAP I need it quick
Ne4ueva [31]

See the attached image.

8 0
3 years ago
When a metal reacts with oxygen gas what is the product formed
beks73 [17]

Answer:

Hello There!!

Explanation:

When a metal reacts with oxygen gas metal oxide forms.Whenever a compound or element reacts with oxygen It turns to oxide.

hope this helps,have a great day!!

~Pinky~

6 0
3 years ago
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