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Tems11 [23]
3 years ago
7

Find the number of Fe2O3 moles needed to release 12 moles of CO2 . ​

Chemistry
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

Explanation:

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A typical virus is 5x10-6 cm in diameter. if avogadro's number of these virus particles were laid in a row, how many kilometers
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Answer is: line be long 3,011·10¹³ kilometers.
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What mass of iron is produced from adding 80.0 g of iron(II) oxide (71.85 g/mol) to 20.0 g of magnesium metal? FeO (l) + Mg (l)
nadya68 [22]

Answer:

46.0g of Iron are produced

Explanation:

Based on the chemical reaction:

FeO(l) + Mg(l) → Fe(l) + MgO(s)

<em>1 mole of Iron (II) oxide reacts per mole of Mg to produce 1 mole of iron</em>

<em />

To solve this question we need to convert each mass of reactant to moles using its respectives molar masses in order to find limitng reactant. Moles of limiting reactant = Moles of iron produced:

<em>Moles FeO (Molar mass: 71.85g/mol):</em>

80.0g * (1mol / 71.85g) = 1.11moles FeO

<em>Moles Mg (Molar mass: 24.305g/mol)</em>

20.0g * (1mol / 24.305g) = 0.823 moles Mg

As moles of Mg < Moles FeO, Mg is limiting reactant and the moles of Fe are 0.823 moles.

The mass of Iron produced is:

0.823 moles Fe * (55.845g/mol) =

46.0g of Iron are produced

6 0
3 years ago
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