In Flourine-19, you can determine that the number of Neutrons is 10.
Now, if you look at Neon-20, you subtract its mass by the number of protons, leaving you with 10.
Therefore, Neon-20 has the same number of neutrons as Flourine-19.
Explanation:
The reaction is as follows:
2Mg(s) + O2(g) ---> 2MgO(s)
and the researcher said that 32 g of MgO was produced.
Stoichiometry:
28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg
15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2
1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO
1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO
0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO
1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO
Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.
Answer:
......... idk use a cheat and look up the answer just helping
<h3><u>Answer;</u></h3>
= 9.45 × 10^23 molecules
<h3><u>Explanation; </u></h3>
The molar mass of Na2SO4 = 142.04 g/mol
Number of moles = mass/molar mass
= 223/142.04
= 1.57 moles
But;
1 mole = 6.02 × 10^23 molecules
Therefore;
1.57 moles = ?
= 1.57 × 6.02 × 10^23 molecules
<u>= 9.45 × 10^23 molecules </u>
Answer:
The answer to your question is 1) 0.037 M 2) 0.32 M 3) 0.096 M
Explanation:
a) 125 ml of 0.251 M HCl
-Calculate the moles of HCl
Molarity = moles/volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.251 x 0.125
= 0.0314
-Calculate the new molarity
Molarity = 0.0314/ (0.125 + 0.250)
-Simplification
Molarity = 0.014/0.375
-Result
Molarity = 0.037 M
2.-
445 ml of 0.499 M of H₂SO₄
-Calculate the number of moles
moles = 0.499 x 0.445
moles = 0.222
-Calculate the new molarity
Molarity = 0.222/(0.445 + 0.25)
Molarity = 0.222/0.695
Molarity = 0.32
3)
5.25 l of HCO₃ 0.101 M
Calculate the number of moles
moles = 0.101 x 5.25
moles = 0.53
-Calculate the Molarity
Molarity = 0.53 / (0.25 + 5.25)
Molarity = 0.53 / 5.5
Molarity = 0.096
