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3 years ago

Hello beautiful people

Chemistry

2 answers:

adoni [48]3 years ago

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ok yes ok yesssssssssssssssssssss

Ainat [17]3 years ago

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Hey how are you doing?

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Which reverse the normal flow of thermal energy

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Heat pumps most do work on a refrigerant in order to reverse the normal flow of thermal energy.

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4 years ago

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What Phase is water at 120 degrees Celsius?

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At atmospheric pressure water boils at 100 degC.
So the water would be gas/vapor/steam.

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3 years ago

You wish to generate 1.00 L of a 0.0750 M NaCl solution by diluting a more concentrated solution. What volume (in mL) of a 0.275

miss Akunina [59]

Taking into account the definition of dilution, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Initial volume</h3>

In this case, you know:

Ci= 0.275 M
Vi= ?
Cf= 0.0750 M
Vf= 1 L

Replacing in the definition of dilution:

0.275 M× Vi= 0.0750 M× 1 L

Solving:

Vi=(0.0750 M× 1 L)÷ 0.275 M

In summary, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

Learn more about dilution:

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2 years ago

How do river systems, watersheds, and divides interact?

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They all end up in the oceon

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3 years ago

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Production of Jam from Crushed Fruit in Two Stages. In a process producing jam (C1), crushed fruit containing 14 wt % soluble so

Andrej [43]

Answer:

The total kg from the mixer: $m=2222.5 kg$

Evaporated water: $m_{water ev.}=791.1 kg$

Jam produced: $m_{jam}=1431.4 kg$

Explanation:

Step by step:

1) Kg of mixture from the mixer

It says that crushed fruit is added to the mixer with the sugar and pectin.

The fruit added is 1000 kg

The sugar added is 1.22 kg sugar/1 kg crushed fruit:

$m_{sugar}=1000 kg fruit * \frac{1.22 kg sugar}{1 kg fruit}=1220 kg sugar$

The pectin added is 0.0025 kg pectin/1 kg crushed fruit:

$m_{pectin}=1000 kg fruit * \frac{0.0025 kg pectin}{1 kg fruit}=2.5 kg pectin$

The total kg from the mixer:

$m=1000 kg fruit + 2.5 kg pectin + 1220 kg sugar=2222.5 kg$

2) Evaporated water

To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:

Initial: 1000 kg of fruit with 14 wt% of solids

$m_{solids}=1000 kg *0.14=140 kg$