Answer:
The percentage of the student is 58.17%.
Explanation:
Expected yield of aluminum oxide = 115.2 g
Actual yield of aluminum oxide produced =66.9 g
The percentage yield is calculated by dividing actual yield by expected yield and then multiplying it with hundred.
Percentage yield:


The percentage of the student is 58.17%.
Answer:
Zinc, copper sulfate
Explanation:
The reactants are the ones on the left side
The lower you go, the more acidic. The higher you go, the more alkaline. Your answer would most likely be 6.
Half-reaction for the cell's anode is given below:
Anode : 
The anode is defined as the electrode at which electrons leave the cell and oxidation occurs, and the cathode as the electrode at which electrons enter the cell and reduction occurs. The anode is usually the positive side.
Learn more about anode here:
brainly.com/question/4052514
Your given question is quite incomplete here is complete question.
A voltaic cell is based on the reduction of _ Agt(aq) to Ag(s) and the oxidation of Sn(s) to Sn2+(aql) : Part 1 Include the phases of all species in the chemical equation: (aqh Anode: Sn(s) Sn?+ (aq)
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