The equilibrium expression shows the ratio
between products and reactants. This expression is equal to the concentration
of the products raised to its coefficient divided by the concentration of the
reactants raised to its coefficient. The correct equilibrium expression for the
given reaction is:<span>
<span>H2CO3(aq) + H2O(l)
= H3O+(aq) + HCO3-1(aq)
Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>
Answer:
Thermal decomposition
Explanation:
The thermal decomposition of amino acids could be carried out at different temperatures and at fixed pressure in a reactor. The effect of temperature on products and pathway could be determined by using time as a function. The hydrothermal decomposition of amino acids takes two key paths
1. The delamination of amino acids to produce ammonia and organi acids
2. The decarboxylation to produce amines and carbonic acids.
The thermal decomposition is and effective experiment that could determine the chemical reaction rate and order of reaction, since it's working with time.
Answer:
1.27 × 10⁵ L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 745 Torr
- Initial volume (V₁): 1.41 × 10⁴ L
- Inital temperature (T₁): 21 °C
- Final pressure (P₂): 63.1 Torr
- Final temperature (T₂): -48 °C
Step 2: Convert the temperatures to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 21 °C + 273.15 = 294 K
K = -48 °C + 273.15 = 225 K
Step 3: Calculate the final volume of the balloon
We will use the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂/ T₁ × P₂
V₂ = 745 Torr × 1.41 × 10⁴ L × 225 K/ 294 K × 63.1 Torr
V₂ = 1.27 × 10⁵ L
part 1 : the final volume : 1.404 L
part 2 : the initial concentration : 4.06 M
<h3>Further explanation
</h3>
Dilution is the process of adding a solvent to get a more dilute solution.
The moles(n) before and after dilution are the same.
Can be formulated :
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
part 1 :
M₁=44.8%
V₁=0.73 L
M₂=23.3%

part 2 :
V₁=739 ml=0.739 L
V₂=1.5 L
M₂=2
