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butalik [34]
3 years ago
6

What kind of nuclear reaction would result in the release of a beta particle

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
3 0
Beta decay converts a neutron to a proton and emits a high-energy electron, producing a daughter nucleus with the same mass number as the parent and an atomic number that is higher by 1.
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PLS HELP what is 2x10^3 in long form
saul85 [17]

Answer:

2x1000 = 2000

Explanation:

10^3 = 10×10×10 = 1000

exponent , the ^3 means multiply the number by itself 3 times, if it was ^4, it would be 4 times and so forth.

another trick for 10s is just put the 1 and the exponents number of 0's after the 1. so in this case, put three 0's: 1,000

6 0
3 years ago
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To use the right hand rule, you should point your thumb in the same
Flauer [41]
The Correct Answer is Eletric Current I think
5 0
4 years ago
Is zinc an example of a element or compound?
Lerok [7]

Answer:

Zinc is an <em>element</em>.

Explanation:

Compounds are composed of two or more elements

3 0
3 years ago
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What is the voltage for the nonspontaneous reaction between silver (Ag) and copper (Cu) and their ions?
gayaneshka [121]
For an non spontaneous reaction between silver (Ag) and copper (Cu) and their ions, Cu is the oxidizing agent while Ag+ is the reducing agent,
The following reactions will take place;
Anode Cu = Cu+2 + 2e-   E= +0.34 volts
Cathode; Ag+ + e = Ag    E = +0.80 volts
The net reaction will be Cu + 2Ag+ = Cu+2 + 2Ag
Thus, the voltage will be
  = +0.80 - (+0.34)
5 0
3 years ago
If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th
mr_godi [17]

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

8 0
3 years ago
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