Answer:
Explanation:
The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:
Initial and final properties are:
. Superheated Vapor.
. Superheated Vapor.
The Joule-Thomson coefficient is approximately:
Answer:
m = x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass