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allochka39001 [22]
3 years ago
9

What force to be required to accelerate a car of mass 120 kg from 5 m/s to 25m/s in 2s​

Physics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:1200

Explanation:

F=ma =m(Vf-Vi)/t

F=120(25-5)/2 =1200N

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Which transformation will map figure L onto figure L'? (1 point) Two congruent triangles Figure L and Figure L prime are drawn o
Ghella [55]

Answer:

Horizontal translation of six units

Explanation:

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3 years ago
Floating piece of wood - buoyancy question.?
sashaice [31]
No. because the weight is the same. no m9re water displacement
7 0
3 years ago
Morse code and string phone cup
polet [3.4K]

Answer:

Following are the responses to the given question:

Explanation:

Following are the difference in the speed and accuracy:

The biggest difference was its tone between both the cup method as well as the Morse code. One should talk using cup system and sequence system and let its covering be understood in Morse code, just a series of beeps weren’t tangible... Secondly, a method of cup involves a range string. Rukun Negara is often distributed by cable, but this is a greater range. It reaches concurrently in those other areas.

In the case of using the string method for the block, its distance and stiffness of the string are limited and the barriers are eliminated. It will certainly be convenient and clearer if one utilizes Sign language.

If two experts are acting like such a machine on both sides, their information between both the 2 persons is smoother and quicker as they will not have to wait for data from a third person which may create another pause at the time.

Morse code is faster, eventually. For some very small periods when sensitive information is not transmitted, strings or cup methods must be reserved.

8 0
3 years ago
The stoplight had just changed and a 2100 kg Cadillac had entered the intersection, heading north at 3.2 m/s , when it was struc
elena55 [62]

Explanation:

It is given that,

Mass of the Cadillac, m_1=2100\ kg

Speed of Cadillac, v_1=3.2\ m/s (towards north)

Mass of Volkswagen, m_2=1100\ kg

The cars stuck together and slid to a halt, leaving skid marks angled 35 degrees north of east.

According to the law of conservation of momentum,

The momentum along x axis, m_1v_1=(m_1+m_2)\ usin35............(1)

The momentum along y axis, m_2v_2=(m_1+m_2)\ ucos35...........(2)

From equation (1) and (2) it is clear that,

\dfrac{m_1v_1}{m_2v_2}=tan35

v_2=\dfrac{m_1v_1}{m_2\ tan35}

v_2=\dfrac{2100\times 3.2}{1100\times \ tan35}

v_2=8.72\ m/s

So, the Volkswagen going just before the impact is 8.72 m/s. Hence, this is the required solution.

6 0
3 years ago
An object is 12 m long, 0.65 m wide, and 13 cm high. Calculate the volume of this object.
ziro4ka [17]

The volume corresponds to the measure of the space occupied by a body. From the given dimensions we can intuit that we are looking to find the Volume of an Cuboid, that is, an orthogonal rectangular prism, whose faces form straight dihedral angles.

Mathematically the volume of this body is given as

V = lWh

Where,

L = Length

W = Width

H = High

V = (12)(0.65)(13*10^{-2})

V = 1.014m^3

Note: The value given for the height was in centimeters, so it was transformed to meters.

6 0
3 years ago
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