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Irina-Kira [14]
3 years ago
11

What should the temperature of the detergent water be in a 3 compartment sink

Chemistry
2 answers:
uysha [10]3 years ago
5 0

The answer is minimum 110°F.

Detergent water's minimum temperature should be between 95°F and 120°F (as hot as anyone can stand) in a 3 compartment sink. In a three compartment sink, the temperature of water should be accurate.This temperature help the detergent work. So the temperature should be maintained by using thermometer that will helps in checking the temperature.

kumpel [21]3 years ago
3 0
It should be At least 110°F
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11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the f
vagabundo [1.1K]

For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as

a) Moles of NaOH =44.05

b)   Moles of Na2CO3=21.0

  • Moles of H2O= 21.0

<h3>What is the moles of NaOH and what moles of each product are formed?</h3>

Generally, the equation for the Chemical reaction  is mathematically given as

2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)

Therefore

Moles of CO2= 925/44

Moles of CO2=21.0

Hence

Moles of NaOH = 2 x Moles of CO2

Moles of NaOH = 2x925/44

Moles of NaOH =44.05

In conclusion

Moles of Na2CO3 925/44

Moles of Na2CO3=21.0

And

Moles of H2O= 925/44

Moles of H2O= 21.0

Read more about Chemical reaction

brainly.com/question/16416932

3 0
2 years ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c
yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

Explanation:

The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

In the reaction:

V2O5(s) + 5Ca(i) → 2V(i) + 5CaO(s)

Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

<em></em>

I hope it helps!

5 0
3 years ago
What is the oxidized substance in the following reaction? <br><br> Fe + 2HCl → FeCl2 + H2
LenKa [72]

Fe⁰ + 2 H⁺¹Cl⁻¹ = Fe⁺²Cl₂⁻¹ + H₂⁰

the iron is oxidized 

the hydrogen is reduced


hope this helps!


4 0
3 years ago
The reaction of NH3 and O2 forms NO and water. The NO can be used to convert P4 to P4O6, forming N2 in the process. The P4O6 can
posledela

Answer : The mass of PH_3 produced from the reaction is, 0.651 grams.

Explanation :

The chemical reactions used are:

(1) 4NH_3+5O_2\rightarrow 4NO+6H_2O

(2) 6NO+P_4\rightarrow P_4O_6+3N_2

(3) P_4O_6+6H_2O\rightarrow 4H_3PO_4

(4) 4H_3PO_4\rightarrow PH_3+3H_3PO_4

First we have to calculate the moles of NH_3

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}

Molar mass of NH_3 = 17 g/mol

\text{Moles of }NH_3=\frac{1.95g}{17g/mol}=0.115mol

Now we have to calculate the moles of NO

From the balanced chemical reaction 1, we conclude that:

As, 4 moles of NH_3 react to give 4 moles of NO

So, 0.115 moles of NH_3 react to give 0.115 moles of NO

Now we have to calculate the moles of P_4O_6

From the balanced chemical reaction 2, we conclude that:

As, 6 moles of NO react to give 1 moles of P_4O_6

So, 0.115 moles of NO react to give \frac{0.115}{6}=0.0192 moles of P_4O_6

Now we have to calculate the moles of H_3PO_4

From the balanced chemical reaction 3, we conclude that:

As, 1 moles of P_4O_6 react to give 4 moles of H_3PO_4

So, 0.0192 moles of P_4O_6 react to give 0.0192\times 4=0.0768 moles of H_3PO_4

Now we have to calculate the moles of PH_3

From the balanced chemical reaction 4, we conclude that:

As, 4 moles of H_3PO_4 react to give 1 moles of PH_3

So, 0.0768 moles of H_3PO_4 react to give \frac{0.0768}{4}=0.0192 moles of PH_3

Now we have to calculate the mass of PH_3

\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3

Molar mass of PH_3 = 33.9 g/mole

\text{ Mass of }PH_3=(0.0192moles)\times (33.9g/mole)=0.651g

Therefore, the mass of PH_3 produced from the reaction is, 0.651 grams.

6 0
3 years ago
Consider the hypothetical reaction 3A + 4B → C + 2D Over an interval of 2.50 s the average rate of change of the concentration o
faust18 [17]

Answer:

Final [B] = 1.665 M

Explanation:

3A + 4B → C + 2D

Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

0.05600 M/s = 4 [B]/ 2.50 s

[B] = 0.035 M (concentration of B consumed)

Final [B] = initial [B] - consumed [B]

Final [B] = 1.700 M - 0.035 M

Final [B] = 1.665 M

3 0
3 years ago
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