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gtnhenbr [62]
3 years ago
5

The angle between A = (-25 m)i +(45 m), and the positive e axis is

Physics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

\theta=119.06^{\circ}

Explanation:

The vector is :

A = -25i+45j

We need to find the angle between angle A and the positive x-axis. It can be calculated as follows :

\theta=180^{\circ}-\tan^{-1} (\dfrac{45}{25})\\\\=180-60.94\\\\=119.06^{\circ}

So, the angle of vector A with the +x axis is 119.06^{\circ}.

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Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
Ainat [17]

Answer:

  • <em>Abbie’s acceleration is (1/2) Zak’s acceleration.</em>

Explanation

1. <u>Data</u>:

a) ω = constant

b) Abbie: r₁ = 1 m

c) Zak: r₂ = 2 m

d) Ac₁ = ? Ac₂

2. <u>Formulae</u>

  • Ac = ω² r

3. <u>Solution</u>:

a) Abbie:

  • Ac₁ = ω² r₁  =  ω² (1m)

b) Zack:

  • Ac₂ = ω² r₂  = ω² (2m)

c) Divide Ac₁ / Ac₂

  • Ac₁ / Ac₂ =  ω² (1m) / [ω² (2m) ] = 1/2

⇒      Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂

5 0
3 years ago
Is brainly even trying anymore?
STALIN [3.7K]
Yes because it helps with my work
7 0
4 years ago
Before the internet was available people often search for jobs?
konstantin123 [22]

Answer:

do you mean how? if so

Explanation:people used newspapersand still kinda do back then they had posters up as they still do and newspapers

5 0
3 years ago
Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an
Setler [38]

The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

<h3>Induced emf</h3>

An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.

emf = NdФ/dt

where;

  • dФ is change in flux of the field
  • N is number of turns
  • dt is change in time

Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

Learn more about induced emf here: brainly.com/question/13744192

#SPJ1

3 0
2 years ago
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,
Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

\int \overrightarrow{F}.d\overrightarrow{x}=\Delta  K.E

\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )

\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times  \left ( v^{2}-0^{2} \right )

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0
3 years ago
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