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3 years ago

The angle between A = (-25 m)i +(45 m), and the positive e axis is

Physics

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer:

$\theta=119.06^{\circ}$

Explanation:

The vector is :

A = -25i+45j

We need to find the angle between angle A and the positive x-axis. It can be calculated as follows :

$\theta=180^{\circ}-\tan^{-1} (\dfrac{45}{25})\\\\=180-60.94\\\\=119.06^{\circ}$

So, the angle of vector A with the +x axis is $119.06^{\circ}$ .

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Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o

Ainat [17]

Answer:

<em>Abbie’s acceleration is (1/2) Zak’s acceleration.</em>

Explanation

1. <u>Data</u>:

a) ω = constant

b) Abbie: r₁ = 1 m

c) Zak: r₂ = 2 m

d) Ac₁ = ? Ac₂

2. <u>Formulae</u>

Ac = ω² r

3. <u>Solution</u>:

a) Abbie:

Ac₁ = ω² r₁ = ω² (1m)

b) Zack:

Ac₂ = ω² r₂ = ω² (2m)

c) Divide Ac₁ / Ac₂

Ac₁ / Ac₂ = ω² (1m) / [ω² (2m) ] = 1/2

⇒ Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂

5 0

3 years ago

Is brainly even trying anymore?

STALIN [3.7K]

Yes because it helps with my work

7 0

4 years ago

Before the internet was available people often search for jobs?

konstantin123 [22]

Answer:

do you mean how? if so

Explanation:people used newspapersand still kinda do back then they had posters up as they still do and newspapers

5 0

3 years ago

Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an

Setler [38]

The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

<h3>Induced emf</h3>

An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.

emf = NdФ/dt

where;

dФ is change in flux of the field
N is number of turns
dt is change in time

Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

Learn more about induced emf here: brainly.com/question/13744192

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2 years ago

A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,

Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

$\int \overrightarrow{F}.d\overrightarrow{x}=\Delta K.E$

$\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )$

$\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times \left ( v^{2}-0^{2} \right )$

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0

3 years ago