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3 years ago

The angle between A = (-25 m)i +(45 m), and the positive e axis is

Physics

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer:

$\theta=119.06^{\circ}$

Explanation:

The vector is :

A = -25i+45j

We need to find the angle between angle A and the positive x-axis. It can be calculated as follows :

$\theta=180^{\circ}-\tan^{-1} (\dfrac{45}{25})\\\\=180-60.94\\\\=119.06^{\circ}$

So, the angle of vector A with the +x axis is $119.06^{\circ}$ .

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HELP!!! I will 5 star if its helpful :(

victus00 [196]

Answer:

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*(MAKE SURE YOU MAKE NOTE OF THE NEGATIVE FORCES AND SUBTRACT THEM!)*

Explanation:

Top left: 17N+25N+25N-42N= 25N

Top right: 65N+200N-65N-150N-200N= 150N

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I hope this helps! :))

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3 years ago

A 0.155 kg arrow is shot upward

Soloha48 [4]

Answer: 244.05 J

Explanation:

To find speed at 30 m above the ground use equation:

V²=Vo²-2Gs

V0=31.4m/s

s=30m

G=9.81m/s²

-----------------------

V²=31.4²-2*9.81*30

V²=985.96+588.6

V²=1574.56

V=39.68m/s ---speed of arrow on 30 m obove the ground

Use equation for kinetic enrgy:

Ke=mV²/2

m=0.155kg

V=39.68m/s

-------------------------

Ke=0.155kg*(39.68m/s)²/2

Ke=0.155*1574.5/2

Ke=244.05J

6 0

3 years ago

A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi

LiRa [457]

Answer:

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

$Q_{in} - W_{out} = \Delta E$

Where:

$Q_{in}$ - Heat absorbed by the gas, measured in joules.

$W_{out}$ - Work done by the gas, measured in joules.

$\Delta E$ - Change in energy, measured in joules.

If we know that $Q_{in} = 1.36\times 10^{2}\,J$ and $W_{out} = 3.19\times 10^{2}\,J$ , the change in energy of the gas is:

$\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J$

$\Delta E = -1.83\times 10^{2}\,J$

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

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3 years ago