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Vinil7 [7]
2 years ago
11

Why did Chief John Ross decided to sign a treaty with Albert Pike? A. The victory at Wilson’s Creek convinced Ross the Confedera

cy would win. B. He was working as a spy for the Union. C. He planned to ignore the treaty and move his tribe west. D. Because his tribe needed money to support their interests during the war.
Chemistry
2 answers:
castortr0y [4]2 years ago
6 0

Answer:

D, i think..

Explanation:

Juliette [100K]2 years ago
5 0

Answer:

It's A.

Explanation:

A.The victory at Wilson's Creek convinced Ross the Confederacy would win.

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Why doesn't light get absorbed
ziro4ka [17]
It isn't a materialistic object.

6 0
2 years ago
Choose the nonmetallic elements from the list. Check all that apply yttrium: oxygen: boron: polonium: argon: gallium: carbon:
BaLLatris [955]

Answer:

B, E, & G

Oxygen, Argon, & Carbon

7 0
3 years ago
Read 2 more answers
A particular voltaic cell operates with the reaction: Zn(s)+Cl2(g)--->Zn^2+(aq)+2Cl^-(aq) giving a cell potential of .853 V.
nadya68 [22]

Answer:

The amount of energy liberated will be 49.38 J.

Explanation:

The amount of energy liberated (gibbs free energy) can be calculated using the following equation:

ΔG° = -nFε

n: amount of moles of electrons transfered

F: Faraday's constant

ε: cell potential

20.0 g of Zn is equal to 0.30 mol.

Two electrons are transfered during the reaction.

Therefore, n = 2x0.30 ∴ n = 0.60

ΔG° = - 0.60 x 96.485 x 0.853

ΔG° = 49.38 J

3 0
3 years ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
2 years ago
How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) +
krek1111 [17]

Answer:  13.9 g of H_2O will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles

The balanced chemical reaction is:

4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)

According to stoichiometry :

7 moles of O_2 produce =  6 moles of H_2O

Thus 0.900 moles of O_2 will produce =\frac{6}{7}\times 0.900=0.771moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g

Thus 13.9 g of H_2O will be produced from the given mass of oxygen

5 0
2 years ago
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