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sveticcg [70]
3 years ago
13

Two substances that have the same number of moles of representative particles always have: Answer the same number of atoms the s

ame masses the same weights none of the above
Chemistry
2 answers:
Nesterboy [21]3 years ago
7 0
<span>same no of atoms
b/c no. of atoms = moles * avogadro's no (6.022 X 10^23)</span>
Allushta [10]3 years ago
6 0

Answer:

the same number of atoms

Explanation:

Mole is defined as amount of substance which contains a fixed number of atoms/molecules/ions/particles and the number is known as Avagadro's number.

One mole is equal to 6.023X10²³ particles of any substance.

For example:

one mole of carbon will have 6.023X10²³ atoms of carbon and one mole of gold will have 6.023X10²³ atoms of gold

Thus the number of atoms will be the same in a given number of moles of any pure element.

Now the mass or weight could not be equal as the mass or weight will depend upon the atomic mass of element.

for example one mole of carbon will weigh 12grams

and one mole of gold will weigh 197grams

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PLEASE HELP!!
grandymaker [24]

Answer:

1. 136 °C.

2. 0.21 atm.

Explanation:

1. Determination of the new temperature in °C.

Initial volume (V1) = 1.35L

Final volume (V2) = 1.95L

Initial temperature (T1) = 283 K

Final temperature (T2) =...?

Using the Charles' law equation, the new temperature of the gas can be obtained as follow:

V1 /T1 = V2 /T2

1.35/283 = 1.95/T2

Cross multiply

1.35 × T2 = 283 × 1.95

1.35 × T2 = 551.85

Divide both side by 1.35

T2 = 551.85/1.35

T2 = 408.8 ≈ 409 K

Finally, we shall convert 409 K to °C. This can be obtained as follow:

T (°C) = T(K) – 273

T(K) = 409 K

T (°C) = 409 – 273

T (°C) = 136 °C

Therefore, the new temperature of the gas is 136 °C.

2. Determination of the new pressure.

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1.67 L

Final pressure (P2) =.?

Next, we shall convert 1.67 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

1.67 L = 1.67 L × 1000 mL / 1 L

1.67 L = 1670 mL

Therefore, 1.67 L is equivalent to 1670 mL.

Finally, we shall determine the new pressure of the gas as follow:

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1670 mL

Final pressure (P2) =.?

P1V1 = P2V2

1.34 × 267 = P2 × 1670

357.78 = P2 × 1670

Divide both side by 1670.

P2 = 357.78 / 1670

P2 = 0.21 atm.

Therefore, the new pressure of the gas is 0.21 atm.

3 0
3 years ago
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