Ca₁₀(PO₄)₆(OH)₂ or Ca(OH)₂·3Ca₃(PO₄)₂
PO₄³⁻ phosphate ion
OH⁻ oxyhydroxide ion
Ca²⁺ calcium ion
10*(+2) + 6*(-3) + 2*(-1) = 0
10Ca²⁺ 6PO₄³⁻ 2OH⁻
Answer:
See explanation below
Explanation:
The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.
Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.
For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)
For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.
It depends on the type of decay that is taking place if its a β+ it will decay into Mn-52 β- decays into Co-59
Answer : The correct option is, Malleable, shiny, and able to conduct heat or electricity.
Explanation:
Metals : Metals are the elements which can easily loose electrons and forms cations.
Properties of metals :
- They are lustrous (shine).
- They are malleable and ductile (flexible).
- They conduct heat and electricity.
- The metallic oxides are basic in nature.
- They form cations in an aqueous solution.
Non-metals : Non-metals are the elements which can easily gain electrons and form an anion.
Properties of non-metals :
- They are non-lustrous.
- They are brittle and hard in nature.
- They do not conduct heat and electricity.
- The non-metallic oxides are acidic in nature.
- They form anions in an aqueous solution.
Hence, from the given options the correct option for metal is, Malleable, shiny, and able to conduct heat or electricity.