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Goryan [66]
3 years ago
11

How many electrons in a ground-state As atom in the gas

Chemistry
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

One electron is the answer if you need work i can show

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1.2 moles of (NH4)3PO3
Aleks04 [339]
1.2 moles of (nph4)3po3 is.......159.6 grams
3 0
2 years ago
What is the concentration of a solution with a volume of 1 L that contain 200 grams of Fe(OH)3?
Goryan [66]

Answer:

0.187M

Explanation:

5 0
2 years ago
What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0
3 years ago
Earthquake foci (Focus, singular) are....
sveta [45]
The answer is the 3rd choice
4 0
3 years ago
Read 2 more answers
A tank in the shape of a rectangular prism measures 10 dm by 4 dm by 6 dm. the tank is completely filled with 8908.8 l of liquid
nevsk [136]
1) The question contains an unknown unit


The number 8908.8 has to be in units of mass: for example, kg or grams.


Here you indicated L.


I am going to work assuming that L is a mass unit. So you can see the way to solve the problem, but you have to verifiy the real unit of the statement and substitute with it.



With that in mind you can find the density of the liquid from:


density  = mass / volume


2) Calculate the volume.


The volume of the liquid is the volume of the vessel, because it is filled.


The volume of the vessel is calculated from the formula of volume for a rectantular prism.


Volume of a rectangular prism = area of the base * height = side * side * height


=> Volume = 10 dm * 4 dm * 6 dm = 240 dm^3 = 240 liter


3) Calculate the density:


density = mass /volume = 8,908.8 L / 240 liter   =  37.12 L / dm^3



Answer: 37.12 L / dm^3


 
6 0
3 years ago
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