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Goryan [66]
4 years ago
11

How many electrons in a ground-state As atom in the gas

Chemistry
1 answer:
LenaWriter [7]4 years ago
3 0

Answer:

One electron is the answer if you need work i can show

You might be interested in
Balance the following equation
mrs_skeptik [129]
The answer would be D. Good luck my dude
3 0
3 years ago
Calculate the number of moles of Cu in 3.8×10213.8×1021 atoms of Cu.
rosijanka [135]

Answer:

6.3×10⁻³ moles of Cu

Explanation:

The relation is, that 1 mol of particles are contained by 6.02×10²³ particles.

This is Avogadro's number that explains that: one mole determines the number of fundamental units that are contained in a constant number  but they do not depend on the type of material or the type of particle, and this quantity is 6.02 × 10²³

We can make a rule of three:

6.02×10²³ atoms are contained 1 in mol of Cu

Therefore, 3.8×10²¹ atoms will be contained in (3.8×10²¹ . 1) / NA = 6.3×10⁻³ moles

7 0
4 years ago
Help please
kipiarov [429]

The correct options are these:

1. It will follow the law of conservation of mass.

2.The mass of products will be equal to the mass of the reactants.

The law of conservation of mass states that ' matter can neither be created nor destroyed. Thus, if a chemical equation is balanced, the mass of the reactant at the beginning of the reaction will be equal to the mass of the product after the reaction. This shows that the chemical reaction obeys the law of conservation of mass.

6 0
3 years ago
Read 2 more answers
just help me with 2a) but if you have a lot of time you can just give me answer for all of it so i can check my answer , thank y
stepladder [879]

Answer:

The reaction forming aluminum bromide is Al + 3Br2 → 2AlBr3

6 0
3 years ago
PLEASE HELPP
rodikova [14]

Answer:

Option (C) 1 × 10^−12

Explanation:

Step 1:

Data obtained from the question include:

[H+] = 1x10^−2

[OH−] =?

Step 2:

Determination of [OH−] . This is illustrated below:

[H+] x [OH−] = 1x10^-14

1x10^−2 x [OH−] = 1x10^-14

Divide both side by 1x10^−2

[OH−] = 1x10^-14 / 1x10^−2

[OH−] = 1x10^-12

Therefore, the [OH−] of the solution is 1x10^-12

7 0
3 years ago
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