You start with 5x+8=10. You want all your constants on one side and variables on the other. So to do that you subtract 8 from both sides, giving you 5x=2. Next you have to divide each side by 2. That gives you 5x/2, or 2.5x. You then take your next equation, 10x+16 and input x. 10(2.5)+16=41.
Your answer is 41 or 10x+16=41
Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
Answer:
Step-by-step explanation:
-81=-5(v+5)-2v Original equation
-81=-5v-25-2v Distributive property
-81=-7v-25 Subtract like terms
-56=-7v Simplify
8=v Simplify
Answer:
5/16
Step-by-step explanation:
multiply 1/2 x 5/8
=5/16
Part A)
A mixed number is in the form where W is any whole number part. The p and q are also whole numbers, which when combined together, form the fractional part p/q
To have a mixed number between 3 and 4, we must make the whole part W equal to 3. The p and q can be anything you want as long as p is smaller than q, this is so p/q is a fraction smaller than 1. So for example, we could have p = 2 and q = 7. So the mixed number is one example of a value between 3 and 4.
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Part B)
This seems to be asking the same exact thing as part A. I'll give another example. The mixed number is between 3 and 4. Again notice the whole part is W = 3. The other two pieces are p = 4 and q = 9. We have p smaller than q.