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Murrr4er [49]
3 years ago
9

Ammonia is produced by the Haber process, in which nitrogen and hydrogen are reacted directly using an iron mesh impregnated wit

h oxides as a catalyst. For the following reaction, equilibrium constants (Kp values) are seen below as a function of temperature.
N2(g) + 3 H2(g) reverse reaction arrow 2 NH3(g)

300°C 4.34 multiplied by 10-3 atm-2
500°C 1.45 multiplied by 10-5 atm-2
600°C 2.25 multiplied by 10-6 atm-2
This is an exothermic reaction, can you explain why it is exothermic and not endothermic?
Chemistry
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer:

Explanation:

The reaction of production of ammonia is as follows

N₂ + 3H₂ ⇄ 2NH₃

From the data given , it is clear that

equilibrium constant decreases as temperature increases . In other words

at higher temperature less and less of ammonia is produced .

According to Le Chatelier's Principle , reaction tends to go in the direction so that the effect of external change is minimized. Since the increase in temperature reduces the forward reaction , that means reaction is exothermic .

So , reduction in reaction , helps reduce the production of heat to reduce the effect of temperature increase.

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Which of the following statements is NOT true?
maria [59]

Answer : The incorrect statements are:

(A) When two nonmetals react, the compound formed is ionic.

(B) Two nonmetals can undergo an oxidation-reduction reaction.

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

The two nonmetals can not undergo an oxidation-reduction reaction.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The metal-nonmetal reaction can always be assumed to be an oxidation-reduction reaction.

For example : 2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

In this reaction, sodium shows oxidation because the oxidation state changes from (0) to (+1) and and chlorine shows reduction because the oxidation state changes from (0) to (-1).

Hence, the incorrect statements are, (A) and (B)

8 0
4 years ago
Calculate the pOH of an aqueous solution of .0.073 M LiOH
Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

<u><em>pOH= 1.14 </em></u>

In summary, the pOH of the aqueous solution is 1.14

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7 0
3 years ago
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