Both <span>b) the weight of jelly beans and c) elevation of a person on a ramp</span>
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
= 0.58 x (56 x 2 + 16 x 3)
= 92.8 grams
Answer:1.309 x 10^24 oxygen atoms
Explanation:
Molar mass of N2O4,= 2 x Molar mass of Nitrogen + 4 x Molar mass of Oxygen
= 2 x 14.01 + 4 x 16.0
= 92.02 g/mol
One mole of a substance is equal to 6.022 × 10²³ unit/ atoms/ molecules
In N2O4, there are 4 moles of Oxygen
if 92.02 g contains = 4 x 6.022 x 10 ^23 molecules
50.0 g wll contain= (4 x 6.022 x 10 ^23 x 50)/ 92.02g
1.309 x 10^24 oxygen atoms
