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givi [52]
4 years ago
8

Using energy considerations, calculate the average force a 60.0-kg sprinter exerts backward on the track to accelerate from 2.00

to 8.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.
Physics
1 answer:
baherus [9]4 years ago
7 0

Answer:

F = 102 N

Explanation:

ASSUMING the track is horizontal to avoid gravity potential energy considerations.

The work of the applied force must overcome friction work and increase the kinetic energy of the runner

F(d) = Ff(d) + ½m(v² - u²)

F = Ff + m(v² - u²) / 2d

F = 30.0 + 60.0(8.00² - 2.00²) / (2(25.0))

F = 102 N

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Answer:

T_0=80695.17162...

Explanation:

Given equation:

\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124

To solve the given equation:

\textsf{Apply log rules}: \quad e^{\ln (x)}=x

\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}

Multiply both sides by T₀:

\implies T_0-100=T_0e^{-0.00124}

Add 100 to both sides:

\implies T_0=T_0e^{-0.00124}+100

Subtract T_0e^{-0.00124} from both sides:

\implies T_0-T_0e^{-0.00124}=100

Factor out the common term T₀:

\implies T_0(1-e^{-0.00124})=100

Divide both sides by (1-e^{-0.00124})

\implies T_0=\dfrac{100}{1-e^{-0.00124}}

Carry out the calculation:

\implies T_0=\dfrac{100}{1-0.99876...}

\implies T_0=\dfrac{100}{0.001239231...}

\implies T_0=80695.17162...

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Explanation:

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