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miss Akunina [59]
3 years ago
12

A liquid phase reaction, A+B à C+D is to be carried out in a well-mixed ideal batch reactor with a constant volume of 10 liters.

The initial concentration of A is 4.71 mol/L, and the initial concentration of B is one half of the initial concentration of A. If the rate of formation of compound D is given by rD = k*CA*CB, with k = 4.5 L/(mol min), calculate the amount of time (in minutes) needed to achieve a conversion of the limiting reactant of 0.86.

Physics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

Explanation:

Given data

  • rate of formation of compound D
  • rD = k*CA*CB
  • Volume V = 10 L
  • initial concentration of A = CA0 = 4.71mol/L
  • Initial concentration of B = one half of the initial concentration of A
  • CB0 = 0.5 x 4.71 mol/L = 2.355 mol/L
  • A + B = C + D
  • From the stoichiometry of the reaction

  • Mol ratio of A : B = 1 : 1

  • moles of A > moles of B

  • B is limiting reactant

  • Rate constant k = 4.5 L/(mol min)

  • -rB = rD = k*CA*CB

  • -rB = k*CA0(1-CB0*X)*CB0(1-X)      

Other detailed steps is as shown in the attached file

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Answer:

(a) q = 2.357 x 10⁻⁵ C

(b) Φ = 2.66 x 10⁶ N.m²/C

Explanation:

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radius of the sphere, r = 1.1 / 2 = 0.55 m

surface charge density, σ = 6.2 µC/m²

(a)  Net charge on the sphere

q = 4πr²σ

where;

4πr² is surface area of the sphere

q is the net charge on the sphere

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