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oksano4ka [1.4K]
2 years ago
10

You see the moon rising, just as the sun is setting. What phase is the moon in?.

Physics
1 answer:
Readme [11.4K]2 years ago
4 0

Answer:

full phase

Explanation:

sorry if its wrong

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How long in seconds will it take a car traveling at 100 miles/hour to travel the length of an American Football field?
Mrrafil [7]

Answer:

It will take 2.45 seconds.

Explanation:

A football field measured 120 yards, that is arround 0.068 miles, the car is moving with a constant speed so the formula we have to apply for this is:

t=\frac{x}{v}\\where\\x=distance\\v=speed\\

t=\frac{0.068}{100}\\t=0.00068hrs

in order to obtain the time in seconds:

tsec=0.00068hr*(\frac{3600sec}{1hr} )\\tsec=2.45 sec

6 0
3 years ago
Help me plz i don’t know the charges on each of these
ivanzaharov [21]

Object B is positively charged, Object C is negatively charged, Object D is negatively charged.

4 0
3 years ago
The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the a
Shtirlitz [24]

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

3 0
3 years ago
The earth exerts the necessary centripetal force on an orbiting satellite to keep it moving in a circle at constant speed. Which
jenyasd209 [6]

Answer:

E) The centripetal force is always perpendicular to the velocity.

Explanation:

Due to gravity and inertia, the satellite follows a uniform circular motion. In this movement, the velocity is always tangent to the orbit and the centripetal force is directed towards the center. Therefore, there is no net acceleration in the same direction of velocity, which implies that it remains constant.

8 0
4 years ago
A 55 kgkg meteorite buries itself 5.5 mm into soft mud. The force between the meteorite and the mud is given by F(x)F(x) = (630
sashaice [31]

Answer:

W = 1.44 10⁻⁷ J

Explanation:

The expression for the job is

          W = ∫ F. dx

Where the point is the scalar product in this case the direction of the meteor and the depth is parallel, whereby the scalar product is reduced to the ordinary product

          W = 630 ∫ x³ dx

          W = 630 x⁴ / 4

Let's evaluate between the lower limit x = 0, w = 0 to the upper limite the point at x = 5.5 10⁻³ m

            W = 157.5 ((5.5 10⁻³)⁴ -0)

            W = 1.44 10⁻⁷ J

6 0
3 years ago
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