All categories

2 years ago

Please help!!! I will give five stars and points for correct answers with a explanation.

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

3 0

Answer:

p-m x n

Step-by-step explanation:

correct

You might be interested in

Pls helppp 1/2•7•24=

Kazeer [188]

Answer:

Step-by-step explanation:

0.5 · 7 · 24

0.5 · 168

3 0

2 years ago

Read 2 more answers

Heyy!!

rosijanka [135]

Answer:

$6^{10}$

Step-by-step explanation:

We can use the following rule of surds to solve the problem:

$\boxed{a^m \times a^n = a^{m + n}}$ ,

which means that when multiplying two numbers with the same bases, we can simply add their powers while keeping the base the same.

Applying this rule:

$6^2 \times 6^8$

⇒ $6^{2 + 8}$

⇒ $\bf 6^{10}$

8 0

1 year ago

Prove the following statement.

gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form $2k+1$ where $k\in \mathbb{Z}$ . Consider the following cases.

Case 1. If $k$ is even we have: $(2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1$ .

If we denote by $m=2s^2+2$ we have that $(2k+1)^{2}=8m+1$ .

Case 2. if $k$ is odd we have: $(2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1$ .

If we denote by $m=2s^{2}+24s+1$ we have that $(2k+1)^{2}=8m+1$

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0

2 years ago

(1/4)^-2 - (5^0) • 1^-1 =

katrin [286]

Answer:

Step-by-step explanation:

8 0

2 years ago

Which point lies on a circle with a radius of 5 units and center at P(6, 1)?

guapka [62]

Answer:

R (2,4)

soln

center(h,k)=(6,1)

radius (r)=5units

eqn of circle is (x-6)^2+(y-1)^2=5^2

2 2

or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle

3 0

2 years ago

Read 2 more answers