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bekas [8.4K]
3 years ago
9

-4(2z+6)-12=4. HAAAAAAAAALP. please include explanation.

Mathematics
2 answers:
DiKsa [7]3 years ago
4 0

Answer:

Z = -5

Step-by-step explanation:

1) multiply bracket

-4 x 2z = - 8z

-4 x 6 = - 24

2) put back into equation

-8z - 24 - 12 =4

3) collect like terms

-8z - 36 =4

4) get z alone

-8z - 36=4

+36 +36

-8z = 40

5) find z

-8z =40

divide both sides by - 8

Z= - 5

Phoenix [80]3 years ago
3 0

Answer:

<h2><em><u>z</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u>5</u></em></h2>

Step-by-step explanation:

-4(2z+6)-12 = 4

=> -8z - 24 - 12 = 4

=> -8z = 4 + 12 + 24

=> -8z = 40

=  > z =  \frac{40}{ - 8}

=> <em><u>z</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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Explain why the expression below always has the same value, no matter what number other than zero you choose for p.
Natasha2012 [34]

Answer and explanation:

The expression P-2P+3P-4P cannot have the same values for different values of P. Let us illustrate this by substituting different values of P in the expression:

If P= 2

Substitute P=2 in the expression

2-2×2+3×2-4×2

=2-4+6-8

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If P= 3

Substitute P=3 in the expression

3-2×3+3×3-4×3

=3-6+9-12

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If P = 1

Substitute P=1 in the expression

1-2×1+3×1-4×1

= 1-2+3-4

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If P = -2

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8 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

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0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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Plug in what we know:

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Multiply 'z' to both sides:

\sf\dfrac{sin(51)}{2.6}z=sin(76)

Divide sin(51)/2.6 to both sides:

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Plug it into your calculator.

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icang [17]

Answer:

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Step-by-step explanation:

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