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2 years ago

Geometry please help asap!

Mathematics

1 answer:

m_a_m_a [10]2 years ago

6 0

Step-by-step explanation:

AB = 3

by similaritiy criterion

CE/ CB= ED/AB

4/6= 2/AB

AB = 3

plz mark my answer as brainlist plzzzz also vote me ..if you find it useful.

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$\bold{ANSWER:}$
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$3y\geqx-9\qquad|:3\\\\y\geq\dfrac{1}{3}x-3\\\\3x+y > -3\qquad|-3x\\\\y > -3x-3$

$\left\{\begin{array}{ccc}y\geq\dfrac{1}{3}x-3\\\\y > -3x-3\end{array}\right$

$y=\dfrac{1}{3}x-3\\\\for\ x=0\to y=\dfrac{1}{3}(0)-3=-3\to(0,\ -3)\\\\for\ x=3\to y=\dfrac{1}{3}(3)-3=1-3=-2\to(3,\ -2)\\\\y=-3x-3\\\\for\ x=0\to y=-3(0)-3=-3\to(0,\ -3)\\\\for\ x=-1\to y=-3(-1)-3=3-3=0\to(-1,\ 0)$

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solid line. we shade above the line

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the dotted line. shadow above the line

Answer in the attachment (the first graph).

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2 years ago

Read 2 more answers

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VikaD [51]

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