Why is there more potential for wind energy in the upper himalayan in nepal?
1 answer:
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Answer:
Explanation:
There are a couple of different ways in which you can solve this and still get the same answer rounded. Since we are talking about KE, I will show you the way that utilizes KE and PE to get the total energy and then figure from that how high the object can go. First off, I'm going to use a mass of 1.0 kg for 2 significant digits. The total energy of a system is found in the equation
TE = PE + KE that says the total energy available to a system is equal to its kinetic energy plus its potential energy. Right off, we are given the KE value of 100 (Even though it's not accurate, I'm going to say that that number has 3 sig fig's, just because rounding to 1 sig fig is counterproductive). If the KE is 100, then
TE = 100 + 0 (the PE is 0 if the object is not moving, which it's not if someone is holding it and then throws it upwards). That's the total amount of energy available to that system and it cannot go up and it cannot go down, it can only change form. If the TE = 100, then we move on to the second part of the problemwhich is finding out how high i can go. The max height of the object indicates that the KE is 0 (the object at its max height isn't moving, even though it's only not moving for a nanosecond. If the object is not moving AND it's at its highest point, KE is 0 and PE is at a max). That means that at this max height,
TE = 0 + PE and filling in the value for TE:
100 = PE and PE = mgh where m is mass, g is the pull of gravity, and h is the height (our unknown).
100 = (1.0)(9.8)(h) and
so, to 2 sig fig's,
h = 1.0 × 10¹ meters (or 10 meters)
b) 747.3 J
a) 7.88 m/s
Explanation:
b)
We start by solving part b) first.
The internal energy generated when crossing the rough patch is equal (in magnitude) to the work done by the friction force on the skier.
The magnitude of the friction force is:
where:
is the coefficient of friction
m = 62.0 kg is the mass of the skier
is the acceleration due to gravity
Therefore, the work done by friction is:
where
d = 4.10 m is the length of the rough patch
The negative sign is due to the fact that the friction force is opposite to the direction of motion of the skier
Substituting,
So, the internal energy generated in crossing the rough patch is 747.3 J.
a)
If we take the bottom of the hill as reference level, the initial mechanical energy of the skier is sum of his kinetic energy + potential energy:
where
m = 62.0 kg is the mass
u = 6.10 m/s is the initial speed
h = 2.50 m is the height of the hill
After crossing the rough patch, the new mechanical energy is
where
W = -747.3 J is the work done by friction
At the bottom of the hill, the final energy is just kinetic energy,
where v is the final speed.
According to the law of conservation of energy, we can write:
So we find v:
1) True.
Uniform circular motion means that the angular velocity
is constant, and since the centripetal acceleration is given by
if
is constant, then a is constant.
2) The correct answer is
<span>a.) the angular velocity and linear velocities are the same
The three knots are in fact on a circle, therefore the angular velocities are the same (because they cover the same angle in the same time) and the linear velocities are the same as well, because it is given by
</span>
and since both r(distance from the center) and are the same, v is also the same.
3) <span>b.) toward the center
In fact, an object can move on a circular path only if there is a force pushing towards the center. This force is called "centripetal force".</span>
Uniform circular motion means that the angular velocity
if
2) The correct answer is
<span>a.) the angular velocity and linear velocities are the same
The three knots are in fact on a circle, therefore the angular velocities are the same (because they cover the same angle in the same time) and the linear velocities are the same as well, because it is given by
</span>
and since both r(distance from the center) and
3) <span>b.) toward the center
In fact, an object can move on a circular path only if there is a force pushing towards the center. This force is called "centripetal force".</span>