<h2>
Hello!</h2>
The answer is:
The kinetic energy of the object is equal to 85 J.
<h2>
Why?</h2>
The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:
Where,
m, is the mas of the object
v, is the speed of the object.
Now, we are given:
So, substituting and calculating the kinetic energy of the object, we have:
We have that the kinetic energy of the object is equal to 85 J.
Have a nice day!
Answer:
t = 0.85[s]
Explanation:
To solve this problem we must make a complete description of this. By doing an internet search, we find the description of this problem as if of the question.
<u>Description</u>
<u />
"An alligator swims to the left with a constant velocity of 5 m s when the alligator season a bird straight ahead the alligator speeds up with a constant acceleration of 3 m/s^2 leftward until it reaches a final velocity of 35 Ms left work how many seconds does it take the alligator to speed up from 5 m/s to 35 m/s".
To solve this problem we must identify the initial data:
v0 = initial velocity = 5 [m/s]
a = acceleration = 3 [m/s^2]
vf = final velocity = 35[m/s]
t = time = ?
Using the following kinematic equation, we can find the time that is required.
![v_{f}=v_{0}+a*t\\35=5+35*t\\t=\frac{35-5}{35} \\t=0.85[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7B0%7D%2Ba%2At%5C%5C35%3D5%2B35%2At%5C%5Ct%3D%5Cfrac%7B35-5%7D%7B35%7D%20%5C%5Ct%3D0.85%5Bs%5D)
Answer:
Einstein had realized in 1905, that space and time, are intimately connected with each other. ... Thus one can think of space and time together, as a four-dimensional entity, called space-time. Each point of space-time is labeled by four numbers, that specify its position in space, and in time.
Explanation:
Answer:
The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)
b) As shown in the FBD the ground reaction forces are:
i) In X direction 
ii) In Y direction 
c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under
Answer:
(a) a= 0.139 m/s²
(b) d= 4.45 m
(c) vf= 1.1 m/s
Explanation:
a) We apply Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass (kg)
a : acceleration (m/s²)
Data
F₁= +2.05 * 10³ N : forward push by a motor
F₂= -1.87* 10³ N : resistive force due to the water.
m= 1300 kg
Calculation of the acceleration of the boat
We replace data in the formula (1):
∑F = m*a
F₁+F₂= m*a
a= 0.139 m/s²
b) Kinematics of the boat
Because the boat moves with uniformly accelerated movement we apply the following formulas:
d= v₀t+ (1/2)*a*t² Formula (2)
vf= v₀+at Formula (3)
Where:
d:displacement in meters (m)
t : time interval (s)
v₀: initial speed (m/s)
vf: final speed (m/s)
a: acceleration (m/s²
)
Data
v₀ = 0
a= 0.139 m/s²
t = 8 s
Calculation of the distance traveled by the boat in 8 s
We replace data in the formula (2)
d= v₀t+ (1/2)*a*t²
d= 0+ (1/2)*(0.139)*(8)²
d= 4.45 m
c) Calculation of the speed of the boat in 8 s
We replace data in the formula (3):
vf= v₀+at
vf= 0+( 0.139)*(8)
vf= 1.1 m/s
