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3 years ago

When dissolved in water, all acids will

Chemistry

2 answers:

yarga [219]3 years ago

8 0

B is the answer I think but I hope it is

poizon [28]3 years ago

7 0

When dissolved in water, acids donate hydrogen ions (H+). Hydrogen ions are hydrogen atoms that have lost an electron and now have just a proton, giving them a positive electrical charge. ... If a solution has a high concentration of H+ ions, then it is acidic.

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If Ca+2 would react with F-1, what do you predict to be the formula

ollegr [7]

It would be CaF2 because you will need to balance then so since F is -1 it'll need another one to balance with Ca +2

3 0

3 years ago

Based on this reaction, find how many moles of co can be obtained starting with 7 mol ch4?

Klio2033 [76]

I will solve the question assuming the reaction used as below
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H<span>2(g)

In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO</span>

5 0

4 years ago

Read 2 more answers

Who discovered the electron?

Sedbober [7]

J.J. Thomson discovered the electron 1897

3 0

3 years ago

90 POINTSSSS!!!

Katarina [22]

Answer:

$\large \boxed{\text{-2043.96 kJ/mol}}$

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)

Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}$

(b)Total enthalpies of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}$

ΔᵣH° is negative, so the reaction is exothermic.

5 0

3 years ago

What is the ph of a 0.014 M HCL solution?

Allushta [10]

Answer:

pH $= 1.853$

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

$[H_3O^+] = [HCl] = 0.014$

pH $= -log [H^+] = -log [H_3O^+]$

Substituting the available values in above equation, we can say that the pH of the solution is equal to

$- log (0.014)$

pH $= 1.853$

pH of a $0.014$ M HCL solution $= 1.853$

8 0

3 years ago