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Nutka1998 [239]
3 years ago
7

a classroom has an aquarium. In the aquarium are a goldfish and a water plant. the teacher explains that both organisms use cell

ular respiration to transform food into energy. identify how the plant and the goldfish get the materials needed for cellular respiration.
Chemistry
1 answer:
Anna71 [15]3 years ago
4 0
the thing that helps is always gonna help that’s why u should always help
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5.81603 miles per hour
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One beaker contains pure water and the other beaker contains pure methanol at the same temperature. Which liquid has the higher
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Water has both the higher surface tension and viscosity

Explanation:

Water has stronger intermolecular forces

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A rigid container (volume cannot change) is filled with carbon dioxide gas at room temperature. The container is then placed in
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The reduction in the temperature leads to an automatic decrease in the pressure of the gas inside the he container. This is due to the decreased number of collisions per unit area of the container walls. Pressure law states that at constant volume, the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.

3 0
4 years ago
How many molecules are there in 0.655 moles of CH_2?
guajiro [1.7K]

Answer:

Not sure about this one, sorry

Explanation:

8 0
3 years ago
PLEASE HELPPP!!!!
aksik [14]

Answer:

b. 11.90 Liters

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>3O₂ + 4Al → 2Al₂O₃,</em>

It is clear that 3.0 moles of O₂ react with 4.0 moles of Al to produce 2.0 Al₂O₃.

  • Firstly, we need to calculate the no. of moles (n) of 36.12 g of Al₂O₃:

<em>n = mass/molar mass</em> = (44.18 g)/(101.96 g/mol) = <em>0.4333 mol.</em>

<u><em>using cross multiplication:</em></u>

3.0 mol of O₂ produces → 2.0 mol of Al₂O₃.

??? mol of O₂ produces → 0.4333 mol of Al₂O₃.

<em>∴ The no. of moles of O₂ needed to produce 36.12 grams of Al₂O₃</em> = (3.0 mol)(0.4333 mol)/(2.0 mol) = <em>0.65 mol.</em>

  • Now, we can find the volume of O₂ used during the experiment:

We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 1.3 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.65 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 290 K).

<em>∴ V = nRT/P </em>= (0.65 mol)(0.0821 L.atm/mol.K)(290 K)/(1.3 atm) = <em>11.9 L.</em>

<em>So, the right choice is: b. 11.90 Liters.</em>

8 0
4 years ago
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