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sdas [7]
3 years ago
8

Name the following compound: CH3-CH2-CH2-CH2-CH3 CH3 CH3

Chemistry
1 answer:
stepan [7]3 years ago
6 0

Answer:

<u><em>Pentane </em></u>

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it C_{5} H_{12}

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Answer:

was difficult to place isotopes of elements as they have the same chemical properties but different atomic masses. It was not possible to predict how many elements could be discovered between two heavy elements as the rise in atomic mass is not uniform.

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3 years ago
Given the equation representing a reversible reaction:which formula represents the h+ acceptor in the forward reaction?
AnnyKZ [126]
Question is incomplete. Complete question is attached below
.............................................................................................................................

Answer: Option A: HCO3-(aq.)

Reason:
From the reaction, it can be seen that following reaction occurs in forward direct

HCO3-(aq)     +     H2O(l)      →      H2CO3(aq)     +      OH-(aq)

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8 0
3 years ago
if the relationship between tempurature and volume of a gas at a constant pressure is linear, explain why the volume of a gas do
Lilit [14]
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4 0
3 years ago
A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

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T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
3 years ago
Which of the following is an example of maintaining homeostasis? A. Learning B. Jumping C. Shivering D. Smiling
yawa3891 [41]

Answer:

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5 0
3 years ago
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