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insens350 [35]
3 years ago
14

What is effects of azeotrope system?​

Chemistry
1 answer:
Ainat [17]3 years ago
4 0

Answer:

An azeotrope or a constant boiling point mixture is a mixture of two or more liquids whose...Such a system of solvents is known as a heteroazeotrope. ... that will affect the volatility of one of the azeotrope constituents more than another.

Explanation:

Azeotrope, in chemistry, a mixture of liquids that has a constant boiling point because the vapor has the same composition as the liquid mixture. The boiling point of an azeotropic mixture may be higher or lower than that of any of its components.

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Nat2105 [25]

The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answer: The temperature is 21.6^{o}C and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Given: Mass = 10 kg

Volume = 14 L

Final pressure = 600 K

First, convert volume from L to m^{3}/kg as follows.

v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg

According to the R-134a tables at 300 kPa and 0.0014 m^{3}/kg.

h_{1} = 54.6 kJ/kg

T_{sat} = 0.7 C

u_{1} = 54.1 kJ/kg

Now, at the state 2 p_{2} = 600 kPa and v_{2} = v_{1} = 0.0014 m^{3}/kg

This means that the final temperature at state 2 is T_{2} = T_{sat} = 21.6^{o}C

Hence, the change in enthalpy is calculated as follows.

\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ

The first law is applied to transfer the heat transfer as follows.

Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ

Thus, we can conclude that the temperature is 21.6^{o}C and total enthalpy when the heating is completed is 300 kJ.

3 0
3 years ago
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