Homologous chromosomes pair up during prophase I to form a ________________.

Chemistry

1 answer:

Ksivusya [100]3 years ago

6 0

I’m pretty sure the correct answer is “tetrad”

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What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

8 0

3 years ago

Which of the following is a unit of length? O A. A liter O B. A kilogram C. A meter O D. A degree

sergeinik [125]

Answer:

C.) A meter

Explanation:

5 0

3 years ago

Which group on the periodic table would have zero electronegativity because they have a full octet?

bija089 [108]

The group on the periodic table that would have 0 electronegativity due to the fact that their valence shell is full, i.e, have a full octet would be the inert or noble gases. They have a total of 8 electrons in their valence shell and are thus inert and cannot strongly attract electrons toward itself, from neighbouring atom electrons as it does not need to.

3 0

3 years ago

3 Na2O(aq) + 2 Al(NO3)3(aq) ----> _ Compound A + _ Compound B

Olin [163]

3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

Hope this helped!

7 0

3 years ago

A solution has a [OH-] of 1 × 10-9. What is the pOH of this solution?

zhannawk [14.2K]

POH = - log [ OH⁻ ]

pOH = - log [ 1 x 10⁻⁹ ]

pOH = 9

Answer C

hope this helps!

3 0

3 years ago