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Pachacha [2.7K]
3 years ago
15

Homologous chromosomes pair up during prophase I to form a ________________.

Chemistry
1 answer:
Ksivusya [100]3 years ago
6 0
I’m pretty sure the correct answer is “tetrad”
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In a bond Between fluorine and bromine which direction will the bond dipole point?
maria [59]

Answer: Bond Polarity | Chemistry for Non-Majors - Lumen Learning

Explanation:

7 0
3 years ago
A gas occupies 25.3 at pressure of 790.5 mmHg. Determine the volume if the pressure is reduced to 8.04 mmHg
taurus [48]

Answer:

2487.51.

Explanation:

As per Boyle's law temperature remaining constant the volume of an ideal gas is inversely proportional to its pressure.

pV= k

therefore, p1V1 = p2V2

here V1 = 25.3, p2 = 8.04mm Hg

pressure p1 = 790.5 mm Hg

this means that

25.3×790.5 = 8.04V2

⇒V2= 2487.51

Hence, the required volume is, 2487.51.

5 0
3 years ago
A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic
user100 [1]
<span> POCl3 is the correct way to write the chemical formula for this compound</span>
5 0
3 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

4 0
3 years ago
Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute.. .
V125BC [204]

Answer:

The water is the solvent and the Carbon Dioxide is the Solute

Explanation:

The Carbon Dioxide is being dissolved into the Water. Solute is what is being dissolved, Solvent is what is doing the dissolving

7 0
3 years ago
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