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adell [148]
3 years ago
5

A 4.44 l container holds 15.4 g of oxygen at 22.55°c. what is the pressure?

Physics
1 answer:
padilas [110]3 years ago
5 0
We will use the ideal gas equation:
PV = nRT, where n is moles and equal to mass / Mr
P = mRT/MrV
P = 15.4 x 8.314 x (22.55 + 273) / 32 x 4.44
P = 266.3 kPa
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If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?
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<h2>It takes 6.78 seconds to complete 12 dribbles.</h2>

Explanation:

Frequency of dribble = 1.77 Hz

That is

         Number of dribbles in 1 second = 1.77

         \texttt{Time taken for 1 dribble = }\frac{1}{1.77}=0.565s

Now we need to find how long does it take for you to complete 12 dribbles.

         Time taken for 12 dribbles = 12 x Time taken for 1 dribble

         Time taken for 12 dribbles = 12 x 0.565

         Time taken for 12 dribbles = 6.78 seconds      

It takes 6.78 seconds to complete 12 dribbles.  

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The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. HW 2 Q2 (a) What is the
Ronch [10]

Answer:

a)<em> 2000 W/m²  </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5

Explanation:

a)

The formula for calculation of total emissive power is:

Total emissive power = E = \int\limits^\alpha_0 E'<em>λdλ</em>

<em>                                    </em>= \int\limits^a_0(0)d<em>λ + </em>\int\limits^b_a(100)d<em>λ + </em>\int\limits^c_b(200)d<em>λ + </em>\int\limits^d_c(100)d<em>λ </em>\int\limits^e_d(0)d<em>λ</em>

<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>

<em>                                    = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>

<em>                                    = 2000 W/m²</em>

b)

The formula for total intensity of radiation is:

I_{e} = E/π = 200/3.14 = 636.94 W/m<em>².sr  </em>

<em>c)</em>

Fo submissive power leaving the surface in range π/4 ≤θ≤π/2

[E(π/4 ≤θ≤π/2)]/E = \int\limits^f_0\int\limits^g_0\int\limits^i_h Icosθsinθ dθdΦdλ

where f = infinity, g=2π, h=π/4, i=π/2

By simplifying, we get

                           = (-1/2)[cos(2π/2)-cos(2π/2)]

                           = -0.5(-1-0)

                           =0.5

8 0
3 years ago
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