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natulia [17]
3 years ago
13

What are the differences between deterministic forces and thermal agitation?

Physics
1 answer:
defon3 years ago
7 0

Answer:

Explanation:

A force is applied to an object and waxes a movement in a certain direction, which can be experimentally medium, all the forces with this behavior are given deterministic, for example: the force of gravity, the pushing of a body, the electrical force, the magnetic force

Thermal agitation is the result of the movement of the bodies in many directions, this movement is due to the collision of the body with each other, which implies a large number of them and it is not possible to define a specific direction, the name of agitation ends is because it is directly related to the temperara

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A marble is placed at Location W. When the marble is released, it rolls down the track.
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Answer:

Z

Explanation:

6 0
2 years ago
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On a topographic map, contour lines create a group of concentric, closed loops. Which of the following features could this indic
posledela

Answer:

b. Hill top

Explanation:

On a topographic map, the closed circles are meant to represent a hill. So if the contour lines are creating a group of concentric closed loops then it must be an indication of a hill.

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3 years ago
A 1.5-kg block slides at rest starts sliding down a snow-covered hill Point A, which has an altitude of 10 m. There is no fricti
damaskus [11]

Answer:

the speed of the block when it reaches point B is 14 m/s

Explanation:

Given that:

mass of the block slides = 1.5 - kg

height = 10 m

Force constant  = 200 N/m

distance of rough surface patch = 20 m

coefficient of kinetic friction = 0.15

In order to determine the speed of the block when it reaches point B.

We consider the equation for the energy conservation in the system which can be represented by:

\dfrac{1}{2}mv^2=mgh

\dfrac{1}{2}v^2=gh

v^2=2 \times g \times   h

v^2=2 \times 9.8 \times   10

v=\sqrt{2 \times 9.8 \times   10

v=\sqrt{196

v = 14 m/s

Thus; the speed of the block when it reaches point B is 14 m/s

7 0
3 years ago
At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Fi
Nataliya [291]

Answer:

The distance from the charge is 3.35 m.                

Explanation:

Given that,

Electric potential, V = 635 V

Magnitude of electric field, E = 189 N/C

We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :

E=\dfrac{V}{d}

d is the distance from charge

d=\dfrac{V}{E}\\\\d=\dfrac{635}{189}\\\\d=3.35\ m

So, the distance from the charge is 3.35 m. Hence, this is the required solution.

8 0
2 years ago
A bicycle racer is going downhill at 11.0 m/s when, to his horror, one of his 2.25 kg wheels comes off when he is 75.0 m above t
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Answer:

a.) Speed V = 29.3 m/s

b.) K.E = 1931.6 J

Explanation: Please find the attached files for the solution

4 0
3 years ago
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