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sukhopar [10]
3 years ago
10

How many atoms are in a molecule of C6H12O6?

Physics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

The answer is 24

Explanation:

Its made up of 6 carbon atoms

6 oxygen atoms

12 hydrogen atoms

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If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in
motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

F_{initial} = \frac{kq_1q_2}{r^2}

Here,

k = Coulomb's constant

q_{1,2} = Charge at each object

r = Distance between them

As the distance is doubled so,

F_{final} = \frac{kq_1q_2}{( 2r )^2}

F_{final} = \frac{ kq_1q_2}{ 4r^2}

F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}

F_{final} = \frac{1}{4} F_{initial}

\frac{F_{final}}{ F_{initial}} = \frac{1}{4}

Therefore the factor is 1/4

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3 years ago
What is the acceleration due to gravity?<br> А<br> B<br> 9.2<br> 12.3<br> С<br> 8.83<br> D<br> 9.81
SCORPION-xisa [38]
Correct answer:

D) 9.81

8 0
3 years ago
An alternating current of 60hz changes direction 100 times per second.
Dvinal [7]

Answer:

False

Explanation:

Because it is 60 hz

7 0
1 year ago
CCDs are _____ format detectors, which detect photons with _____ efficiency. analog, high analog, low digital, high digital, low
mars1129 [50]
High digital and high are the answers.

hope this helps
7 0
3 years ago
Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book &am
stich3 [128]

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}

\frac{1}{Req45}=\frac{1}{5}+\frac{1}{4}

\frac{1}{Req45}=0.2+0.25=0.45\\ Req45=2.22

Now, this equivalent Req45 is in series with R3, therefore:

Req345=R3+Req45\\Req345=4+2.22\\Req345=6.22

This Req345 is in parallel with R2, i.e

Req2345=(R2^{-1}+Req345^{-1}  )^{-1}\\ Req2345=(4^{-1}+6.22^{-1}  )^{-1} \\Req2345=2.43

Now this gets in series with R1:

Req12345=R1+Req2345\\Req12345=9+2.43\\Req12345=11.43

Now, the power delivered Ws is:

Ws=Vs*I=\frac{Vs^{2}}{Req}  \\Ws=\frac{10^{2} }{11.43} \\Ws=8.75 Watts

8 0
3 years ago
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