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konstantin123 [22]
3 years ago
8

When the amplitude of a wave triples, the intensity changes by a factor of [blank](1/3,1/9,3,9)

Physics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer:

1. It becomes 9 times.

2. it becomes one fourth times.

3. It becomes one hundredth times.

4. It becomes one ninth times.

Explanation:

Intensity of a wave is directly proportional to the square of amplitude of the wave and inversely proportional to the square of the distance between the source and observation point.

1. As the amplitude of the wave is tripled, the intensity becomes 9 times.

2. As the amplitude becomes half, the intensity becomes one fourth.

3. As the distance between the source and the ear is one tenth, the intensity becomes one hundredth.

4. As the distance between source and ear is one third, the intensity becomes one ninth.

sladkih [1.3K]3 years ago
5 0

1.  9

2. 1/4

3.  1/100

4.  9

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In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1
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Answer:

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Explanation:

Total charge in a single droplet, q=-9.6\times 10^{-19}\ C

The measured charge of any single droplet, e=-1.6\times 10^{-19}\ C

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

q=ne

n=\dfrac{q}{e}

n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}

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So, there are 6 electrons contained within the drop. Hence, this is the required solution.

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During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.​
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A thin rod of length 1.4 m and mass 140 g is suspended freely from one end. It is pulled to one side and then allowed to swing l
m_a_m_a [10]

Answer:

a The kinetic energy is  KE = 0.0543 J

b The height of the center of mass above that position is  h = 1.372 \ m    

Explanation:

From the question we are told that

  The length of the rod is  L = 1.4m

   The mass of the rod m = 140 = \frac{140}{1000} = 0.140 \ kg  

   The angular speed at the lowest point is w = 1.09 \ rad/s

Generally moment of inertia of the rod about an axis that passes through its one end is

                   I = \frac{mL^2}{3}  

Substituting values

               I = \frac{(0.140) (1.4)^2}{3}

               I = 0.0915 \ kg \cdot m^2

Generally the  kinetic energy rod is mathematically represented as

             KE = \frac{1}{2} Iw^2

                    KE = \frac{1}{2} (0.0915) (1.09)^2

                           KE = 0.0543 J

From the law of conservation of energy

The kinetic energy of the rod during motion =  The potential energy of the rod at the highest point

   Therefore

                   KE = PE = mgh

                        0.0543 = mgh

                             h = \frac{0.0543}{9.8 * 0.140}

                                h = 1.372 \ m    

                 

5 0
3 years ago
Read 2 more answers
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