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3 years ago

When the amplitude of a wave triples, the intensity changes by a factor of [blank](1/3,1/9,3,9)

Physics

2 answers:

trasher [3.6K]3 years ago

6 0

Answer:

1. It becomes 9 times.

2. it becomes one fourth times.

3. It becomes one hundredth times.

4. It becomes one ninth times.

Explanation:

Intensity of a wave is directly proportional to the square of amplitude of the wave and inversely proportional to the square of the distance between the source and observation point.

1. As the amplitude of the wave is tripled, the intensity becomes 9 times.

2. As the amplitude becomes half, the intensity becomes one fourth.

3. As the distance between the source and the ear is one tenth, the intensity becomes one hundredth.

4. As the distance between source and ear is one third, the intensity becomes one ninth.

sladkih [1.3K]3 years ago

5 0

1. 9

2. 1/4

3. 1/100

4. 9

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Sonia was experimenting with electric charges. She tied two inflated balloons together, held them next to each other, and rubbed

lions [1.4K]

Answer: They will repel each other.

Explanation:

Two inflated balloons when rubbed with woolen cloth will lead to repeal each other because of the similar charges on both the balloons.

Rubbing both the balloons together by the woolen cloth will introduce negative charge in the balloons.

As, we know that the same charges repeal each other both of the balloons with be apart from each other.

This is due to the static electricity, the negatively charged particles jump to the positive one. When balloons are rubbed they become negatively charged.

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3 years ago

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A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1. 5 second

madreJ [45]

The force involved is = 25200 Newton

Given the values in the questions,

Mass = 1400 kg

Speed or velocity of the car = 27 m/s

Time is given = 1.5 seconds

According to the formula of force,

⇒ Force = Mass x Acceleration

⇒ Force = 1400 x Acceleration ----- equation 1

Now to calculate the value of acceleration we will use,

⇒ Acceleration = (Velocity or Speed) / Time

⇒ Acceleration = 27 / 1.5

⇒ Acceleration = 18 m/ $s^{2}$

Putting the value of acceleration in equation 1,

⇒ Force = 1400 x 18

⇒ Force = 25200 Newton

Therefore, the force involved is = 25200 Newton

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8 0

1 year ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
$1 rev= 2 \pi rad$
$1 min = 60 s$
the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
$v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s$

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3 years ago

Ur a genius if u explain how it’s A correctly

Alinara [238K]

Answer:

Explanation:

4/1=4

3/2=1.5

2/3=0.666667

1/4=0.25

D has the least number so its D

6 0

2 years ago

If two micro coulomb of charge is flowing in a circuit for 5 minutes. What is the amount of current in the circuit?

Murrr4er [49]

Answer:

6.67×10¯⁹ A

Explanation:

From the question given above, the following data were obtained:

Quantity of electricity (Q) = 2 μC

Time (t) = 5 mins

Current (I) =?

Next, we shall convert 2 μC to C. This can be obtained as follow:

1 μC = 1×10¯⁶ C

Therefore,

2 μC = 2 μC × 1×10¯⁶ C / 1 μC

2 μC = 2×10¯⁶ C

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 secs

Therefore,

5 min = 5 min × 60 sec / 1 min

5 mins = 300 s

Finally, we shall determine the current in the circuit. This can be obtained as follow:

Quantity of electricity (Q) = 2×10¯⁶ C

Time (t) = 300 s

Current (I) =?

Q = It

2×10¯⁶ = I × 300

Divide both side by 300

I = 2×10¯⁶ / 300

I = 6.67×10¯⁹ A

Thus, the current in the circuit is 6.67×10¯⁹ A

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2 years ago