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Illusion [34]
3 years ago
12

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.40 m/s

in 0.792 s. What are:______
a. the magnitudes of the linear impulse
b. the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates?
Physics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

a) 378Ns

b) 477.27N

Explanation:

Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula

I = Ft = m(v-u)

m is the mass = 70kg

v is the final velocity = 5.4m/s

u is the initial velocity = 0m/s

Get the impulse

I = m(v-u)

I = 70(5.4-0)

I = 70(5.4)

I = 378Ns

b) Average total force is expressed as

F = ma (Newton's second law)

F = m(v-u)/t

F = 378/0.792

F = 477.27N

Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N

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State the state the first law of motion
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3 0
4 years ago
Water, initially saturated vapor at 4 bar, fills a closed, rigid container. The water is heated until its temperature is 360°C.
salantis [7]

Explanation:

Using table A-3, we will obtain the properties of saturated water as follows.

Hence, pressure is given as p = 4 bar.

u_{1} = u_{g} = 2553.6 kJ/kg

v_{1} = v_{g} = 0.4625 m^{3}/kg

At state 2, we will obtain the properties. In a closed rigid container, the specific volume will remain constant.

Also, the specific volume saturated vapor at state 1 and 2 becomes equal. So, v_{2} = v_{g} = 0.4625 m^{3}/kg

According to the table A-4, properties of superheated water vapor will obtain the internal energy for state 2 at v_{2} = v_{g} = 0.4625 m^{3}/kg and temperature T_{2} = 360^{o}C so that it will fall in between range of pressure p = 5.0 bar and p = 7.0 bar.

Now, using interpolation we will find the internal energy as follows.

 u_{2} = u_{\text{at 5 bar, 400^{o}C}} + (\frac{v_{2} - v_{\text{at 5 bar, 400^{o}C}}}{v_{\text{at 7 bar, 400^{o}C - v_{at 5 bar, 400^{o}C}}}})(u_{at 7 bar, 400^{o}C - u_{at 5 bar, 400^{o}C}})

     u_{2} = 2963.2 + (\frac{0.4625 - 0.6173}{0.4397 - 0.6173})(2960.9 - 2963.2)

                   = 2963.2 - 2.005

                   = 2961.195 kJ/kg

Now, we will calculate the heat transfer in the system by applying the equation of energy balance as follows.

      Q - W = \Delta U + \Delta K.E + \Delta P.E ......... (1)

Since, the container is rigid so work will be equal to zero and the effects of both kinetic energy and potential energy can be ignored.

            \Delta K.E = \Delta P.E = 0

Now, equation will be as follows.

           Q - W = \Delta U + \Delta K.E + \Delta P.E

           Q - 0 = \Delta U + 0 + 0

           Q = \Delta U

Now, we will obtain the heat transfer per unit mass as follows.

          \frac{Q}{m} = \Delta u

         \frac{Q}{m} = u_{2} - u_{1}

                      = (2961.195 - 2553.6)

                      = 407.595 kJ/kg

Thus, we can conclude that the heat transfer is 407.595 kJ/kg.

4 0
3 years ago
An individual is nearsighted; his near point is 18.0 cm and his far point is 40.0 cm.
swat32

Answer

given,

near point = 18 cm

far point = 40 cm

a) The lens should form an upright, virtual image at far point from the distant object.

therefore, f = q  = -40 cm = -0.4 m

where f is the focal length.

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b) If the lens is used the Person's near point

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    p = \dfrac{qf}{q-f}

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3 0
3 years ago
5. An astronaut has a mass of 65kg where the gravitational field strength is 10N/kg
spayn [35]

Answer:  a) weight on Earth = mass of the object and gravity n the Earth. = 65*10 = 650 kg.

Explanation:

An astronaut has a mass of 65 kg on Earth where the gravitational field strength is 10 N kg A calculate the astronaut's weight on Earth

          hope this helps :)

3 0
3 years ago
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