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Illusion [34]
3 years ago
12

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.40 m/s

in 0.792 s. What are:______
a. the magnitudes of the linear impulse
b. the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates?
Physics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

a) 378Ns

b) 477.27N

Explanation:

Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula

I = Ft = m(v-u)

m is the mass = 70kg

v is the final velocity = 5.4m/s

u is the initial velocity = 0m/s

Get the impulse

I = m(v-u)

I = 70(5.4-0)

I = 70(5.4)

I = 378Ns

b) Average total force is expressed as

F = ma (Newton's second law)

F = m(v-u)/t

F = 378/0.792

F = 477.27N

Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N

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kondaur [170]

Answer with Explanation:

The force of attraction between 2 charges of magnitudeq_1,q_2 separated by a distance 'r' is given by

F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}

where

\epsilon _o is a constant known as permitivity of free space

k=9\times 10^{9}Nm^2/C^2

Applying the given values in the above relation we get

8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters

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Movement of a stationary object (2words)
Whitepunk [10]
Induced motion or movement
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The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were obser
ELEN [110]

Answer:

a)  v² = G M R³,  b)  T = 2π /\sqrt{GMR}, c)  m \sqrt{GMR^5 }

Explanation:

a) The kinetic energy is

         K = ½ m v²

       

to find the velocity let's use Newton's second law

          F = m a

acceleration is centripetal

           a = v² / R

           

force is the universal force of attraction

           F = G m M / r²

we substitute

          G m M R² = m v² R

          v² = G M R³

           

the kinetic energy is

          K = ½ m G M R³

b) angular and linear velocity are related

          v = w R

          w = v / R

          w = \frac{\sqrt{GMR^3  }}{R}

          w = \sqrt{GMR}

the angular velocity is related to the period

          w = 2π / T

          T = 2π / w

we substitute

           T = 2π /\sqrt{GMR}

c) the angular moeomto is

            L = m v r

            L = m RA G M R³ R

            L =  m \sqrt{GMR^5 }

4 0
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he summit of Mount Everest is 8850 m above sea level. (a) How much energy would a 78 kg climber expend against the gravitational
natali 33 [55]

Answer:

The energy which is expend by the person is U=6.7\times 10^{6}J.

Explanation:

The formula for the potential energy due to the height of the object is as follows as;

U= mgh

Here, h is the height of the person, m is the mass of the object and g is the acceleration due to gravity.

It is given in the problem that a person is 8850 m above the sea level. 78 kg climber would expend energy against the gravitational force in climbing to the summit from sea level. Here, the person has potential energy as he is above the sea level.

Put h= 8850 m, m= 78 kg and  g = 9.8 m s^{-2} and  in the above expression to get the value of energy.

U= (78)(9.8)(8850)

U= 6764940 J

U=6.7\times 10^{6}J

Therefore, the energy which is expend by the person is U=6.7\times 10^{6}J.

8 0
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Colt1911 [192]

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Water does not remain locked up in the oceans,  icecaps, groundwater systems , or the atmosphere. Instead water is continually moving from one reservoir to another. This movement of water is called the hydrologic cycle.

Although water in the hydrologic cycle is constantly in motion, it never leaves the earth. The earth is nearly a "closed system" like a terrarium. This means the earth neither gains nor loses much matter, including water.

7 0
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