By a black hole, the sky looks normal then the stars closer to the black holes look like they are spinning around the black hole.
Given Information:
Mass of electron = m = 9x10⁻³¹ kg
initial speed of electron = v₁ = 0.92c
Force = F = 1.4x10⁻¹³ J
Distance = d = 3 m
Required Information:
Final speed of electron = v₂ = ?
Answer:
Final speed of electron = v₂ = 2.974x10⁸ m/s
Explanation:
As we know from the conservation of energy,
E₂ - E₁ = W
E₂ = E₁ + W
Where E₂ is the final energy of electron and E₁ is the initial energy of electron
The above equation can be written in the form of particle energy
γ₂mc² = γ₁mc² + W
where γ₁ and γ₂ are given by
γ₁ = 1/√1 - (v₁/c)²
γ₂ = 1/√1 - (v₂/c)²
First calculate γ₁
γ₁ = 1/√1 - (0.92c/c)²
γ₁ = 2.55 m
Now calculate γ₂
γ₂ = (γ₁mc² + W)/mc²
First we need to find the work done
W = F*d
W = 1.4x10⁻¹³*3
W = 4.2x10⁻¹³ J
so γ₂ is
γ₂ = (2.55*9x10⁻³¹*(3x10⁸)² + 4.2x10⁻¹³)/9x10⁻³¹*(3x10⁸)²
γ₂ = 7.73
Now we can find the new speed of the electron
γ₂ = 1/√1 - (v₂/c)²
Re-arranging the above equation results in
v₂ = c*√(1 - 1/γ₂²)
v₂ = 3x10⁸*√(1 - 1/7.73²)
v₂ = 2.974x10⁸ m/s
Electrical to light & electrical to sound (in commentry) & sometimes battery loudspeakers are used so chemical to sound
Answer:
893 Newtons
Explanation:
m = Mass of Usain Bolt = 94 kg
a = Acceleration of Usain Bolt in the first 0.89 seconds = 9.5 m/s²
From Newton's Second law
Force
The average horizontal force exerted by Bolt against the ground during the first 0.890 s of the race is 893 Newtons
Answer:
114.075 N
798.525 Nm
Explanation:
C = Drag coefficient = 0.5
ρ = Density of air = 1.2 kg/m³
A = Surface area = 9 m²
v = Velocity of wind = 6.5 m/s
r = Height of the tree = 7 m
Drag equation
Magnitude of the drag force of the wind on the canopy is 114.075 N
Toque is given by the product of force and radius
Torque exerted on the tree, measured about the point where the trunk meets the ground is 798.525 Nm
