Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and 
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf
Where, B = magnetic field
l = length
v = velocity
Put the value into the formula
We need to calculate the induced current
Put the value into the formula
(b). We need to calculate the power dissipated through the resistor
Using formula of power
Put the value into the formula
Hence, The induced current and the power dissipated through the resistor are 0.5 mA and .
Increasing the number of bulbs in a series circuit decreases the brightness of the bulbs. In a series circuit, the voltage is equally distributed among all of the bulbs. Bulbs in parallel are brighter than bulbs in series. In a parallel circuit the voltage for each bulb is the same as the voltage in the circuit.
Answer: Part(a)=0.041 secs, Part(b)=0.041 secs
Explanation: Firstly we assume that only the gravitational acceleration is acting on the basket ball player i.e. there is no air friction
now we know that
a=-9.81 m/s^2 ( negative because it is pulling the player downwards)
we also know that
s=76 cm= 0.76 m ( maximum s)
using kinetic equation
where v is final velocity which is zero at max height and u is it initial
hence
now we can find time in the 15 cm ascent
using quadratic formula
t=0.0409 sec
the answer for the part b will be the same
To find the answer for the part b we can find the velocity at 15 cm height similarly using
where s=0.76-0.15
as the player has traveled the above distance to reach 15cm to the bottom
when the player reaches the bottom it has the same velocity with which it started which is 3.861
hence the time required to reach the bottom 15cm is
t=0.0409
Answer:
197.76 m
Explanation:
r = Radius of the path = 20.6 km = 
= The angle subtended by moon = 
Distance traveled is given by
The distance traveled by the jet is 197.76 m
