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svetlana [45]
3 years ago
14

A foam cup with negligible specific heat is used as a calorimeter. If you mix 175 g of water at 20.0°C and 125 g of water at 95.

0°C, what is the final temperature of the water after it is mixed? Assume no loss of heat to the air or container. (the specific heat of water= 4186 J/Kg.oC)
Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

T = 51.25°C

Explanation:

Applying the law of conservation of energy, we get:

where,

m₁ = mass of cold water = 175 g

m₂ = mass of hot water = 125 g

T = Final temperature of the mixture = ?

Therefore,

(175\ g)(T-20^oC) = (125\ g)(95^oC-T)\\\\T-20^oC = (0.7143)(95^oC-T)\\\\T(1+0.7143) = 20^oC+67.86^oC\\\\T = \frac{87.86^oC}{1.7143}

<u>T = 51.25°C</u>

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