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VLD [36.1K]
3 years ago
6

What is the size of the force acting on a copper wire with a magnetic flux density of 3.6 x 10-2 T acting at

Physics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

F = 0.414 N

Explanation:

Given that,

Magnetic flux density,B=3.6\times 10^{-2}\ T

The length of the wire, l = 24 m

Current, I = 0.48 A

We need to find the force acting on the wire. The formula for the force is given by:

F=ILB

Put all the values,

F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N

So, the force acting on the copper wire is equal to 0.414 N.

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Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

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Distance travelled by car B (D₆) = 150 Km

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