If you draw one card from a standard deck, what is the theoretical probability of drawing a face card? *
1 answer:
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Y = 3x + 1
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)
Answer:
∠TAC is approximately equal to 61.6°
Step-by-step explanation:
The given parameters for the pyramid are;
The dimension for the rectangular base are; Length = 9 cm, width = 7 cm
The length of the diagonal sides, TA, TB, TC, and TD = 12 cm each
The midpoint of the rectangular base = Point M
The diagonal AC = AM + MC
AM = MC as given M is the midpoint of the rectangular base
∴ AC = AM + MC = 2·AM
By Pythagoras' theorem, AC = √(9² + 7²) = √130
AC = √130 cm
∴ AM = AC/2 = (√130)/2 cm
Alternatively, AM = √((9/2 cm)² + (7/2 cm)²) = √(32.5) cm
∠TAC = ∠TAM
By trigonometric ratios, we have;