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2 years ago

What causes an atom to be neutral?

Physics

1 answer:

Ugo [173]2 years ago

4 0

Answer:

Explanation:

If there are the same number of protons (+) as electrons (-) they will cancel out and make the atom neutral.

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What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?

Mrac [35]

The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.

7 0

3 years ago

Read 2 more answers

The sound produced by the loudspeaker in the drawing has a frequency of 11999 Hz and arrives at the microphone via two different

const2013 [10]

The speed at which sound travels through the gas in the tube is 719.94m/s

Explanation:

Given:

Frequency, f = 11999Hz

Wavelength, λ = 0.03m

Velocity, v = ?

Sound speed in the tube is calculated by multiplying the frequency v by the wavelength λ.

As the sound loudness changed from a maximum to a minimum, then we know the sound interference in the case changed from constructive interference (the two sound waves are in phase, i.e. peaks are in a line with peaks and so the troughs), to a destructive interference (peaks coinciding with troughs). The least distance change required to cause such a change is a half wavelength distance, so:

λ/2 = 0.03/2

λ = 0.06m

We know,

v = λf

v = 0.06 X 11999Hz

v = 719.94m/s

Therefore, the speed at which sound travels through the gas in the tube is 719.94m/s

3 0

3 years ago

Radio waves travel at a speed of 1.7 times 10^8 m/s through ice. A radio wave pulse sent into the Antarctic ice reflects off the

Nostrana [21]

The values with (1/2)(9.8 m/s2) (4 - X)^2 = (1.7 × 10^8 m/s) (X) —> We discover with the calculator X = 4.40 × 10^-7. The depth of the ice is then calculated by multiplying by the speed 74.8 m. Through ice, radio waves move at a speed of 1.7 x 108 m/s.

What is radio waves?

A radio wave pulse that is delivered into the Antarctic ice returns after reflecting off the bottom rock. A radio wave pulse that is transmitted into the Antarctic ice bounces off the subsurface rock and resurfaces. ice in Antarctica Through ice, radio waves move at a speed of 1.7 108 m/s. The rock reflects the radio wave pulse that was transmitted into the Antarctic ice. The amount of time that passed between the signal being sent and being received by the earth station.

To learn more about Antarctic from given link

brainly.com/question/3200132

#SPJ4

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9 months ago

A speed-time graph is shown below:

alexandr1967 [171]

Answer:

The average acceleration of the object is 0.5 cm/s^2. Answer: A)

Explanation:

Average Acceleration

The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

$\displaystyle \bar a=\frac{v_f-v_o}{t}$

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

$\displaystyle \bar a=\frac{4-0}{8}=0.5$

The average acceleration is 0.5 cm/s^2

A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

C) Incorrect. The average acceleration is 0.5 cm/s^2

D) Incorrect. The average acceleration is 0.5 cm/s^2

3 0

3 years ago

Car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver not

musickatia [10]

Answer:

Part A: $t = v_0/a_0$

Part B: $t = v_0/a_0$

Part C: $v_0^2/a_0$

Explanation:

Part A:

We will use the following kinematics equation:

$v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}$

Part B:

We will use the same kinematics equation:

$v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}$

Part C:

The total time takes is 2t.

So the train moves a distance of

$x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}$

And the car moves a distance in Part A and in Part B:

$d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}$

So the total distance that the car traveled is $d = \frac{v_0^2}{a_0}$

The difference between the train and the car is

$x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}$

8 0

3 years ago