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Lelu [443]
4 years ago
15

When making a sound source near a reflective surface, such as making a person at a podium, the sound can reflect off of the surf

ace an create phase interference known as comb filtering. An approach to solve this problem is...
Physics
1 answer:
Liula [17]4 years ago
5 0

Answer:

1. By removing the reflector or reflecting elements

2. By using absorbing material on the reflecting surfaces.

Explanation:

To solve problems caused by reflecting surfaces, you can remove the reflector or reflecting elements. However, sometimes it is enough to turn/move the reflecting element and change the reflections. Furthermore, using absorbing material on the reflecting surface can help reduce comb filtering as well.

In some cases, it is possible to place the sound source so close to the reflecting surface, that there is no suspension between the direct sound and the reflected sound.

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Atoms with an atomic mass greater than___ May undergo fission
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56

Explanation:

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4 years ago
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A cart, which has a mass of m - 2.50 kg, is sitting at the top of an inclined plane which is 3.30 meters long and which meets th
SashulF [63]

Answer:

Part(i) the time taken for this cart to reach the bottom of the inclined plane is 1.457 s

Part(ii) the velocity of the cart when it reaches the bottom of the inclined plane is 4.531 m/s

Part(iii) the kinetic energy of the cart when it reaches the bottom of the inclined plane is 25.663 J

Explanation:

Given;

mass of the cart = 2.5 kg

angle of inclination, β = 18.5⁰

length of inclined plane = 3.3m

Part(i) the time taken for this cart to reach the bottom of the inclined plane

s = ut + ¹/₂×at²

initial vertical velocity, u = 0

s = 3.3 m

s =  ¹/₂×at²

t = \sqrt{\frac{2s}{a} }

acceleration, of the cart, a = gsinβ

a = 9.8sin(18.5) = 3.11 m/s²

t = \sqrt{\frac{2X3.3}{3.11 }}= 1.457 s

Part(ii) the velocity of the cart when it reaches the bottom of the inclined plane

V = a×t

V = 3.11 × 1.457 = 4.531 m/s

Part(iii) the kinetic energy of the cart when it reaches the bottom of the inclined plane

KE = ¹/₂MV²

    = ¹/₂ × 2.5× (4.531)²

    = 25.663 J

6 0
4 years ago
How far will a rubber ball fall in 10 seconds?
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If it's not moving at all at the beginning of the 10 seconds, then it falls 490 meters straight down in 10 seconds.

(Note: This is true of all objects on Earth . . . rubber balls, feathers, grains of sand, school buses, battle ships . . . everything.  As long as air doesn't hold them back.  Anything falling from rest falls 490 meters in the first 10 seconds.)

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3 years ago
As an astronaunt travels from the surface of the earth to a postion that is four times
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Answer:

Explanation:

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While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is
erica [24]

Answer:

The answer is "4-5-6 because the bank is growing too quickly in the beginning of its turn".

Explanation:

The S-turns is also known as the reference technique, in which the ground track of the aircraft on both sides of a defined ground-based straight-line distance represents 2 different but equivalent circles.  

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